The intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
<h3>How to determine the intersection of the lines?</h3>
The lines are given as:
y = -14x + 3 and y = -32x+3
Substitute y = -32x+3 in
-32x+3 = -14x + 3
Evaluate the like terms
-18x = 0
Divide by -18
x = 0
Substitute x = 0 in y = -14x + 3
y = -14(0) + 3
Evaluate
y = 3
Hence, the intersection of lines y=-14x+3 and y=-32x+3 is (0, 3)
Read more about linear equations at:
brainly.com/question/14323743
#SPJ1
Answer:
0.00187393
Hope this helps! :)
Please mark me the Brainliest!
You can create a right angled triangle.
Find the hypotenuse.
The third point of the triangle is (1,0)
using pythagoras, the value of a is 2, b is 3. 2^2 +3^2 = 13.
Therefore the distance between the two points is