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GalinKa [24]
3 years ago
11

What is the equation of a line that goes through (9,-1) and is perpendicular to line 2y-3x=8

Mathematics
1 answer:
jonny [76]3 years ago
7 0
Choicexs?














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Please help!<br><br> If sin(xº)=cos(yº) find k if x=2k+3 and y=6k+7
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answer

10

step-by-step explanation

the equation given is sin(x) = cos(y) with x = 2k + 3 and y = 6k + 7

substitute in 2k+ 3 for x in sin(x) and substitute in 6k + 7 for y in cos(y)

sin(x) = cos(y)

sin(2k + 3) = cos(6k + 7)

we know that sin(x) = cos(90 -x)

sin(2k + 3)

= cos(90 - (2k + 3) )

= cos(90 - 2k - 3)

= cos(87 - 2k)

substitute this into the equation sin(2k + 3) = cos(6k + 7)

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3 years ago
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7 0
3 years ago
Read 2 more answers
HELPPPPPPPPPPPPPPPPPP
Finger [1]

Answer:

Given expression : \frac{9}{4}-2(4x+\frac{4}{3} )+\frac{5}{2}x    ......[1]

Using distributive property:  a\cdot (b+c) =a\cdot b + a\cdot c

[1]⇒   \frac{9}{4} - 2(4x) - 2(\frac{4}{3})+\frac{5}{2} x

Simplify:

\frac{9}{4} - 8x - \frac{8}{3}+\frac{5}{2}x

Like terms are those terms which are same variables.

Combine like terms: we get;

(\frac{9}{4} - \frac{8}{3}) - 8x + \frac{5}{2}x            ......[2]

\frac{27-32}{12} -8x +\frac{5}{2} x

Simplify:

\frac{-5}{12} -8x +\frac{5}{2}x  

or

\frac{-5}{12} - \frac{11}{2}x  

we can write equation [2] as;

\frac{27}{12} - \frac{8}{3} - 8x + \frac{5}{2}x

Combine like terms of x variables;

\frac{27}{12} - \frac{8}{3} - \frac{11}{2}x

Therefore, the expressions which are equivalent to the Given expression are:

\frac{9}{4} - 2(4x) - 2(\frac{4}{3})+\frac{5}{2} x

\frac{-5}{12} -8x +\frac{5}{2}x  

\frac{27}{12} - \frac{8}{3} - \frac{11}{2}x

\frac{-11}{2}x - \frac{5}{2}





3 0
3 years ago
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