solution is (4, - 7 )
given the equations
y = 2x - 15 → (1)
4x + 3y = - 5 → (2)
substitute y = 2x - 15 into (2)
4x + 3(2x - 15) = - 5
4x + 6x - 45 = - 5
10x - 45 = - 5 ( add 45 to both sides )
10x = 40 ( divide both sides by 10 )
x = 4
substitute x = 4 into (1) for corresponding value of y
y = (2 × 4 ) - 15 = 8 - 15 = - 7
solution is (4, - 7 )
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
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So based on the given problem above, it says that, for one batch with 3/4 cup of brown sugar can make 6 dozen big cookies. If we are to make 15 dozen cookies, what we need to do is to divide 3/4 cup of brown sugar by 6 dozen, and we get 0.125. This means that per dozen, it is equivalent to 0.125 cup of brown sugar. If we multiply it by 15 dozens, we get 1.875 cup or 1 and 7/8 cup of brown sugar. Hope this answer helps.
Given:
A circle is centered on point B.
Points A, C and D lie on its circumference.
If
measures 40°.
To find:
The
.
Solution:
Central angle theorem: According to this theorem, the central angle is equal to the twice of inscribed angle on the same intercepted arc.
In the given figure
is the central angle and
is the inscribed angle on the same arc AC.
Using central angle theorem, we get




Therefore, the measure of angle ADC is 20°.