That’s hard lol but it’s angle 5 to the power of 7.t!$/&:
Okay so I am going to summarize the work out process because its a lot to
Here we go
1/3 (t) + 3/4 - 2/4 - t = ?
1/2 (simplify )
(1/3 (T)+3/4 - 1/2 - (t) = ?
t (2) / 2
1 - 2(t) / 2 = ?
3/4 (simplify this )
1/3(t)+ 3/4 - [1 - 2(t) / 2 = ?
1/3 (this is re last one you have to simplify)
L (Denominator): 3
R (Denominator): 4
L: [L.C.M] : 4
R: [L.C.M] : 3
Basically , we just switched the dominators around
So, Therefore The of t is -3/16
T = -3/16
Answer:
A = -12
B = -8
C = -4
Step-by-step explanation:
![y=2x-8](https://tex.z-dn.net/?f=y%3D2x-8)
x = -2
![y=2(-2)-8=-4-8=-12](https://tex.z-dn.net/?f=y%3D2%28-2%29-8%3D-4-8%3D-12)
A = -12
x = 0
![y = 2 (0)-8=-8](https://tex.z-dn.net/?f=y%20%3D%202%20%280%29-8%3D-8)
B = -8
x = 2
![y = 2 (2) -8 = 4-8 = -4](https://tex.z-dn.net/?f=y%20%3D%202%20%282%29%20-8%20%3D%204-8%20%3D%20-4)
C = -4
Hope this helps
36 feet to metres = 10.97
first find the final velocity
vf^2 = vi^2 + 2ad
vf^2 = 0 + 2(9.81)(10.97)
vf^2 = 215.2314
vf = 14.6708
vf = vi + at
at = vf - vi
t = (vf - vi)/a
t = (14.6708)/9.81
t = 1.4955seconds