Answer: Length axis f= 114.3 Hz, Width axis f=228.67 Hz
Explanation:
We are given that,
Length of tub= 1.5 m
Width of tub= 0.75 m
Sound speed= 343 m/s
Now, we are also given shower is closed.
So, frequency is given as:
f=
For length axis
Put v= 343 m/s, m=1 and L=1.5 m
f= 1 *
f= 114.3 Hz
For next resonant frequency, m=2
f= 2*
f= 228.67
For width axis
Put v= 343 m/s, m=1 and L= 0.75 m
f= 1*
f= 228.67 Hz
For next frequency, m=2
f= 2*
f= 457.34 Hz
Answer : The correct option is, (d) 4 times
Solution :
According to the Coulomb's law, the electrostatic force of attraction or repulsion between two charges is directly proportional to the product of the charges and is inversely proportional to the square of the distance between the the charges.
Formula used :
where,
F = electrostatic force of attraction or repulsion
= Coulomb's constant
and
are the charges
r = distance between two charges
First we have to calculate the force exerted between S and q when the distance between the charge is 1 unit and let us assumed that the charge be 'q'
..........(1)
Now we have to calculate the force exerted between S and p when the distance between the charge is 2 unit at the same charge.
...........(2)
Equation equation 1 and 2, we get
Therefore, the force exerted between S and q is 4 times the force exerted between S and p.