Answer:
262.5Pa
Explanation:
Given parameters:
P1 = 175Pa
T1 = 300K
T2 = 450K
Unknown:
P2 = ?
Solution:
To solve this problem, we are going to use an adaptation of the combined gas law.
=
Insert the parameters and solve;
=
P2 = 262.5Pa
Answer:
(a). The required is 1871.2 J.
(b). The speed the lead bullet is 395 m/s.
(c). The 20% of energy must have gone into collision between steel plate and bullet.
Explanation:
Given that,
Mass of bullet = 0.030 kg
Temperature = 20°C
(a). We need to heat required to increase the temperature of the lead bullet and melt it
Using formula of heat
Where, m = mass of lead bullet
S = specific heat
L = latent heat
T = Temperature
Put the value into the formula
The required is 1871.2 J.
(b). Assume that 80% of the bullet’s kinetic energy goes into increasing its temperature and then melting it
We need to calculate the energy
We need to calculate the speed the lead bullet
Using formula of speed
The speed the lead bullet is 395 m/s.
(c). The 20% of energy must have gone into collision between steel plate and bullet.
Hence, This is the required solution.
Answer:2 ft/s
Explanation:
Given
Length of Pole is 9 ft
Length of Joe is 3 ft
Joe walks away from Pole at the rate 4 ft/s
Let Joe is x m away from Pole so its shadow length is x'
From Similar triangle concept
3x'=x+x'
x=2x'
and it is given
Differentiating