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3 years ago

Find the y-component of this

Physics

1 answer:

murzikaleks [220]3 years ago

3 0

Answer:

Fy = 101sin 42.2

Fy = 101(0.672)

Fy= 67.9m

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Which is not a characteristic of chemical energy? A. chemical change B. breaking bonds C. splitting nuclei D. reacting substance

Delvig [45]

The correct answer is C. Splitting Nuclei.

Splitting nuclei is not a characteristics of chemical energy.

Chemical energy is termed as the energy which results when there is chemical reaction. Chemical energy is being stored in molecules which makes substance and bonds of atoms.

In order for our bodies to function well they need chemical energy. During photosynthesis plants perform chemical reaction each and every day.

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3 years ago

Read 2 more answers

How do the characteristics of a liquid differ from a solid? All BUT ONE applies.

andreyandreev [35.5K]

Answer:

D) intermolecular attraction deceased

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3 years ago

Why is the moon’s surface cratered, but the Earth’s is not

Scorpion4ik [409]

The comets hit the moon's surface because there is no atmosphere on the moon to protect it. The earth has an atmosphere so it is protected.

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3 years ago

A high-speed K0 meson is traveling at β = 0.90 when it decays into a π + and a π − meson. What are the greatest and least speeds

san4es73 [151]

Answer:

greatest speed=0.99c

least speed=0.283c

Explanation:

To solve this problem, we have to go to frame of center of mass.

Total available energy fo π + and π - mesons will be difference in their rest energy:

$E_{0,K_{0} }-2E_{0,\pi } =497Mev-2*139.5Mev\\$

=218 Mev

now we have to assume that both meson have same kinetic energy so each will have K=109 Mev from following equation for kinetic energy we have,

K=(γ-1) $E_{0,\pi }$

$K=E_{0,\pi}(\frac{1}{\sqrt{1-\beta ^{2} } } -1)\\\frac{1}\sqrt{1-\beta ^{2} }}=\frac{K}{E_{0,\pi}}+1\\ {1-\beta ^{2}=\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta ^{2}=1-\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta = +-\sqrt{\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\\\\beta =+-\sqrt{1-\frac{1}{(\frac{109Mev}{139.5Mev+1)^2}}$

$u'=+-0.283c$

note +-=±

To find speed least and greatest speed of meson we would use relativistic velocity addition equations:

$u=\frac{u'+v}{1+\frac{v}{c^{2} } } u'\\u_{max} =\frac{u'_{+} +v_{} }{1+\frac{v}{c^{2} } } u'_{+} \\u_{max} =\frac{0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } 0.828\\ u_{max} =0.99c\\u_{min} =\frac{u'_{-} +v_{} }{1+\frac{v}{c^{2} } } u'_{-}\\u_{min} =\frac{-0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } -0.828c\\u_{min} =0.283c$

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3 years ago

The principle of conservation of energystates that energy is neither created nor destroyed. Which of thefollowing describes the

bezimeni [28]

Answer: the statement that describes the transformation of energy is statement B (The potential energy was turned into Albertine's kinetic energy, which was then converted into internal(thermal) energy.)

Explanation:

Law of conservation of energy states that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

Throughout Albertine's journey, no energy was lost. Her potential energy was converted to kinetic energy and then to thermal energy of the body.

5 0

3 years ago