For classical kinematics, you usually graph position versus time, meaning D. This would be a graph where time is on the x-axis and position (can also be treated as displacement if you consider the net distance) is on the y axis.
Answer:
A) 3.48m/s
B) 3.92m
C) 2.32m
D 23.33m/s
Explanation:
ma(t)=mg-At
a(t)= g - (At/m)
V(t)= integrala(T)dT = gt- (At^2/2m)
Initial x coordinator of the box is zero
X(t)= integralV(t)dt= 1/2gt^2-(At^3/6m)
a) V =( 9.81×1) -(38×1^2/2×3)
V= 9.81-6.33= 3.48m/s
b)-AT^2/2m + gT= 0
T=2mg/A= (2×3×9.81)/38
T= 1.549m
X(T)= (1/2×9.81×1.549^3)- (38×1.549^3/6×3)
X(T)= 11.768- (141.23/18) = 11.768 - 7.85= 3.92m
C) 1/2gT''^2 - AT''^3/6m =0
The only non trivial solution is T''= 3mg/A
T=(3×3×9.81)/38 = 2.32m
D) V = 9.81×3) - (38×3^2/6)
V= 29 - 5.667= 23.33m/s
Answer:
Gran Telescopio Canarias
Explanation:
There are numerous giant telescopes all over the world which give us amazingly details data of the Universe. These work in various wavelengths. Talking about the telescopes which operates in visible wavelengths, the largest operational telescope will be Gran Telescopio Canarias. This telescope has an aperture of 10.4m. It is situated in Canary Island, Spain.
In future larger telescopes such as Thirty Meter Telescope and EELT will will make it look like a small telescope.
Exposure of a Photographic plate to Uranium in a closed space along with a metal that prevented the rays from passing through best helped becquerel determine Uranium radiates rays.