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Makovka662 [10]
3 years ago
11

Prior to the development of e-commerce, web sites primarily delivered static html pages. true

Computers and Technology
1 answer:
CaHeK987 [17]3 years ago
8 0
<span>Prior to the development of e-commerce, web sites primarily delivered static HTML pages. true</span>
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Write a C program (doublecopy) that allows a user to extract some part of an existing file (fileSource) and copy it twice to a n
Slav-nsk [51]

Answer:

Check the explanation

Explanation:

#include <stdio.h>

#include <sys/stat.h>

#include <stdlib.h>

#include <fcntl.h>

#include <errno.h>

#include <unistd.h>

extern int errno;

struct stat st;

int main(int argc, char **argv){

  int num1 = atoi(argv[1]); // Getting num1 from user

  int num2 = atoi(argv[2]); // Getting num2 from user

  char *fileSource = argv[3];

  char *fileTarget = argv[4];

 

  int source_fd = open(fileSource, O_RDONLY); // opening the file in read only mode

  int target_fd = open(fileTarget, O_WRONLY | O_CREAT); // opening the target file in Writeonly mode if file is not found it will create

   

  char *ch = (char *) calloc(num2+num1, sizeof(char));

 

  stat(fileSource, &st);

  if(st.st_size < (num1 + num2)){

      printf("File Size is smaller than the specified bytes\n");

      read(source_fd, ch, st.st_size); // reading the file upto the end

      write(target_fd, ch, st.st_size); // write to the file

      write(target_fd, ch, st.st_size); // two times writing to the file

  }else{

      if(lseek(source_fd, (off_t)num1, SEEK_SET) < 0 ) // moving the cursor to after the specified bytes from the start

      {

          printf("Some Error occured while seeking the file");

          return -1;

      }

      read(source_fd, ch, num2); // reading num2 bytes from the source

      write(target_fd, ch, num2); // writing two times to the target

      write(target_fd, ch, num2);

     

  }

 

  return 0;

 

}

1 2 #include <stdio.h> #include <sys/stat.h> #include <stdlib.h> #include <fcntl.h> #include <errno.h> #include <unistd.h> 4

The code screenshot and code output are attached below.

3 0
3 years ago
What would be the total width of the div in the code below?
Artyom0805 [142]

Answer:

The answer to this question is given below in the explanation section.

Explanation:

The correct answer to this question is d- 346px.

The complete code of this example is given below:

<div>

style="margin:20px; border:solid 3px #888888;">

</div>

while the image width is 300px.

It is noted that the image width is 300px and the margin is 20 px.

Margin:20px means that image margin from four side is 20 px each.

So the width of dive from both side increase to 40 px and the image has 300 px, then total width becomes 340px. Now the border also has 3px of four sides of the image, then the width of the border becomes 6px.

so the total width of the div tag is 346 px.

In short, we can calculate the width of tag as below:

total width of div= width of image+ width of margin+ width of border

total width of dive= 300px+40px+6px

total width of div=346px.

4 0
2 years ago
Read 2 more answers
Consider the following algorithms. Each algorithm operates on a list containing n elements, where n is a very large integer.
DochEvi [55]

We have that the appropriate statement will be

  • An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

From the question we are told

Consider the following <u>algorithms</u>. Each <u>algorithm</u> operates on a list containing n <em>elements</em>, where n is a very large <u>integer</u>.

I. An algorithm that accesses each <u>element</u> in the list twice.

II. An <em>algorithm </em>that accesses each <u>element </u>in the list n times.

III. An <u>algorithm</u> that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the <em>algorithms </em>run in <em>reasonable </em>time?

<h3>Algorithm  </h3>

Generally In order to get <em>admission </em>to every thing in the list twice, the algorithm has to traverse the listing twice,

which leads to 2*n entry to operations.

And if the every factor is accessed n times, the listing will be traversed n time, which leads to n^2 get right of entry to operations.

If n is a very giant <em>integer</em>, each 2*n and n^2 are plenty larger.

So, there will be <em>solely </em>ten entry to operations and this algorithm will have a sensible jogging time.

Therefore

An algorithm that accesses only the first 10 elements in the list, regardless of the size of the list. Which of the algorithms run in reasonable time

III only.

Option B

For more information on  algorithm  visit

brainly.com/question/950632

4 0
2 years ago
What two names are given to the blinking vertical line?
Paha777 [63]

Answer:

<u>see </u><u>below</u><u>:</u>

Explanation:

One is (the cursor).

Whenever you see a flashing vertical line called-the cursor--you can start typing.Note that the mouse pointer is also called a cursor,but it is shaped differently.The keyboard cursor is also called the insertion point.

5 0
3 years ago
Give the type and value of each result of the following Java expressions.
atroni [7]
Give the type and value of each result of the following Java expressions. a. (5 / 2) * 2.0  type is float value is 4.0 b. (5/2.0) * 2 type is integer value is 5c. "1.3" + "5.2" type is string value is 1.35.2d. 1 + 7.0 + "2" + "x"  this will produce an error because we cannot add variables of different type
3 0
3 years ago
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