A driving license number has 6 digits (between 1 to 9). The first two digits are 12 in that order, that third digit third digit
is bigger than 6, the fourth one can be equally divided divided by 3 and the fifth digit is 3 times bigger than sixth one. How many license numbers can be made using this arrangement? 27, 36, 72, 112 ...?
The counting principle is applied for this problem. There is only one possible combinations for the first two digits: 12. There are four possible combinations for the third digit: 7, 8, 9, 10. There are three possible combinations for the fourth digit: 3, 6, 9. There are three possible combinations for the fifth and sixth digits: 31, 62, 93.
So all in all, 1(4)(3)(3) = 36.
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