Answer:
It's indeed A. Yet I think of reporting multiple same questions as spam and nonsense titles.
but nah, I won't, would be kinda focused on the toxic part then :D
Answer:
D
Step-by-step explanation:
EXPLORE test is the college test ACT's "prep" version mostly for 8th and 9th graders.
ASVAB (Armed Services Vocational Aptitude Battery) test is used for military entrance exam.
PLAN is also like EXPLORE that it is a "prep" test for ACT but usually given to sophomore (10th grade) students. This has been discontinued from 2014, though.
SAT is a standardized test administered by College Board and is a widely used common Undergraduate University admissions exam. Colleges use this to make admissions decisions.
Thus, D is the correct choice.
A. -17.1
the minus sign makes the first number a negative, and a negative plus a negative you add normally but put a negative sign in your answer
Answer:
One solution
Step-by-step explanation:
5x + y = 8
15x + 15y = 14
Lets solve using substitution, first we need to turn "5x + = 8" into "y = mx + b" or slope - intercept form
So we solve for "y" in the equation "5x + y = 8"
5x + y = 8
Step 1: Subtract 5x from both sides.
5x + y − 5x = 8 − 5x
Step 2: 5x subtracted by 5x cancel out and "8 - 5x" are flipped
y = −5x + 8
Now we can solve using substitution:
We substitute "-5x + 8" into the equation "15x + 15y = 14" for y
So it would look like this:
15x + 15(-5x + 8) = 14
Now we just solve for x
15x + (15)(−5x) + (15)(8) = 14(Distribute)
15x − 75x + 120 = 14
(15x − 75x) + (120) = 14(Combine Like Terms)
−60x + 120 = 14
Step 2: Subtract 120 from both sides.
−60x + 120 − 120 = 14 − 120
−60x = −106
Divide both sides by -60
![\dfrac{ -60x }{ -60 } = \dfrac{ -106 }{ -60 }](https://tex.z-dn.net/?f=%5Cdfrac%7B%20-60x%20%20%7D%7B%20-60%20%20%7D%20%20%20%3D%20%20%20%5Cdfrac%7B%20-106%20%20%7D%7B%20-60%20%20%7D)
Simplify
![x = \dfrac{ 53 }{ 30 }](https://tex.z-dn.net/?f=x%20%3D%20%20%20%5Cdfrac%7B%2053%20%20%7D%7B%2030%20%20%7D)
Now that we know the value of x, we can solve for y in any of the equations, but let's use the equation "y = −5x + 8"
![\mathrm{So\:it\:would\:look\:like\:this:\ y = -5 \left( \dfrac{ 53 }{ 30 } \right) +8}](https://tex.z-dn.net/?f=%5Cmathrm%7BSo%5C%3Ait%5C%3Awould%5C%3Alook%5C%3Alike%5C%3Athis%3A%5C%20y%20%3D%20%20-5%20%5Cleft%28%20%20%5Cdfrac%7B%2053%20%20%7D%7B%2030%20%20%7D%20%20%20%20%5Cright%29%20%20%2B8%7D)
![\mathrm{Now\:lets\:solve\:for\:"y"\:then}](https://tex.z-dn.net/?f=%5Cmathrm%7BNow%5C%3Alets%5C%3Asolve%5C%3Afor%5C%3A%22y%22%5C%3Athen%7D)
![y = -5 \left( \dfrac{ 53 }{ 30 } \right) +8}](https://tex.z-dn.net/?f=y%20%3D%20%20-5%20%5Cleft%28%20%20%5Cdfrac%7B%2053%20%20%7D%7B%2030%20%20%7D%20%20%20%20%5Cright%29%20%20%2B8%7D)
![\mathrm{Express\: -5 \times \dfrac{ 53 }{ 30 }\:as\:a\:single\:fraction}](https://tex.z-dn.net/?f=%5Cmathrm%7BExpress%5C%3A%20-5%20%5Ctimes%20%20%20%5Cdfrac%7B%2053%20%20%7D%7B%2030%20%20%7D%5C%3Aas%5C%3Aa%5C%3Asingle%5C%3Afraction%7D)
![y = \dfrac{ -5 \times 53 }{ 30 } +8](https://tex.z-dn.net/?f=y%20%3D%20%20%20%5Cdfrac%7B%20-5%20%5Ctimes%20%2053%20%20%7D%7B%2030%20%20%7D%20%20%2B8)
![\mathrm{Multiply\:-5 \:and\:53\:to\:get\:-265 }](https://tex.z-dn.net/?f=%5Cmathrm%7BMultiply%5C%3A-5%20%5C%3Aand%5C%3A53%5C%3Ato%5C%3Aget%5C%3A-265%20%7D)
![y = \dfrac{ -265 }{ 30 } +8](https://tex.z-dn.net/?f=y%20%3D%20%20%20%5Cdfrac%7B%20-265%20%20%7D%7B%2030%20%20%7D%20%20%2B8)
![\mathrm{Simplify\: \dfrac{ -265 }{ 30 } \:,by\:dividing\:both\:-265\:and\:30\:by\:5} }](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%5C%3A%20%20%5Cdfrac%7B%20-265%20%20%7D%7B%2030%20%20%7D%20%20%20%20%5C%3A%2Cby%5C%3Adividing%5C%3Aboth%5C%3A-265%5C%3Aand%5C%3A30%5C%3Aby%5C%3A5%7D%20%7D)
![y = \dfrac{ -265 \div 5 }{ 30 \div 5 } +8](https://tex.z-dn.net/?f=y%20%3D%20%20%20%5Cdfrac%7B%20-265%20%5Cdiv%20%205%20%20%7D%7B%2030%20%5Cdiv%20%205%20%20%7D%20%20%2B8)
![\mathrm{Simplify}](https://tex.z-dn.net/?f=%5Cmathrm%7BSimplify%7D)
![y = - \dfrac{ 53 }{ 6 } +8](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%5Cdfrac%7B%2053%20%20%7D%7B%206%20%20%7D%20%20%2B8)
![\mathrm{Turn\:8\:into\:a\:fraction\:that\:has\:the\:same\:denominator\:as\: - \dfrac{ 53 }{ 6 }}](https://tex.z-dn.net/?f=%5Cmathrm%7BTurn%5C%3A8%5C%3Ainto%5C%3Aa%5C%3Afraction%5C%3Athat%5C%3Ahas%5C%3Athe%5C%3Asame%5C%3Adenominator%5C%3Aas%5C%3A%20-%20%5Cdfrac%7B%2053%20%20%7D%7B%206%20%20%7D%7D)
![\mathrm{Multiples\:of\:1: \:1,2,3,4,5,6}](https://tex.z-dn.net/?f=%5Cmathrm%7BMultiples%5C%3Aof%5C%3A1%3A%20%5C%3A1%2C2%2C3%2C4%2C5%2C6%7D)
![\mathrm{Multiples\:of\:6: \:6,12,18,24,30,36,42,48}](https://tex.z-dn.net/?f=%5Cmathrm%7BMultiples%5C%3Aof%5C%3A6%3A%20%5C%3A6%2C12%2C18%2C24%2C30%2C36%2C42%2C48%7D)
![\mathrm{Convert\:8\:to\:fraction\:\dfrac{ 48 }{ 6 }}](https://tex.z-dn.net/?f=%5Cmathrm%7BConvert%5C%3A8%5C%3Ato%5C%3Afraction%5C%3A%5Cdfrac%7B%2048%20%20%7D%7B%206%20%20%7D%7D)
![y = - \dfrac{ 53 }{ 6 } + \dfrac{ 48 }{ 6 }](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%5Cdfrac%7B%2053%20%20%7D%7B%206%20%20%7D%20%20%2B%20%5Cdfrac%7B%2048%20%20%7D%7B%206%20%20%7D)
![\mathrm{Since\: - \dfrac{ 53 }{ 6 }\:have\:the\:same\:denominator\:,\:add\:them\:by\:adding\:their\:numerators}](https://tex.z-dn.net/?f=%5Cmathrm%7BSince%5C%3A%20-%20%5Cdfrac%7B%2053%20%20%7D%7B%206%20%20%7D%5C%3Ahave%5C%3Athe%5C%3Asame%5C%3Adenominator%5C%3A%2C%5C%3Aadd%5C%3Athem%5C%3Aby%5C%3Aadding%5C%3Atheir%5C%3Anumerators%7D)
![y = \dfrac{ -53+48 }{ 6 }](https://tex.z-dn.net/?f=y%20%3D%20%20%20%5Cdfrac%7B%20-53%2B48%20%20%7D%7B%206%20%20%7D)
![\mathrm{Add\: -53 \: and\: 48\: to\: get\: -5}](https://tex.z-dn.net/?f=%5Cmathrm%7BAdd%5C%3A%20-53%20%5C%3A%20and%5C%3A%2048%5C%3A%20to%5C%3A%20get%5C%3A%20%20-5%7D)
![y = - \dfrac{ 5 }{ 6 }](https://tex.z-dn.net/?f=y%20%3D%20%20-%20%5Cdfrac%7B%205%20%20%7D%7B%206%20%20%7D)
![\mathrm{The\:solution\:is\:the\:ordered\:pair\:(\dfrac{ 53 }{ 30 }, - \dfrac{ 5 }{ 6 })}](https://tex.z-dn.net/?f=%5Cmathrm%7BThe%5C%3Asolution%5C%3Ais%5C%3Athe%5C%3Aordered%5C%3Apair%5C%3A%28%5Cdfrac%7B%2053%20%20%7D%7B%2030%20%20%7D%2C%20-%20%5Cdfrac%7B%205%20%20%7D%7B%206%20%20%7D%29%7D)
So there is only one solution to the equation.
Answers;
it would be the second one
Step-by-step explanation:
hope this helps