We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where 
represents the number of objects/people in the set and 
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
The answer is B. You will get that after multiplying 12.99 by 4, and then calculate the tax and add 2.50
Answer:
P(3) = 0.0244
P(3) = 2.44%
the probability that all three selected have driven while under the influence of alcohol is 2.44% or 0.0244
Step-by-step explanation:
Given;
The probability that they have driven while under the influence of alcohol is;
P = 29% = 0.29
the probability that all three selected have driven while under the influence of alcohol is;
P(3) = P × P × P
P(3) = 0.29 × 0.29 × 0.29
P(3) = 0.024389
P(3) = 0.0244
P(3) = 2.44%
the probability that all three selected have driven while under the influence of alcohol is 2.44% or 0.0244
Answer:
200 divided by 1.325 = 0.006625 thats how big each penny is hope this helped! :)
Step-by-step explanation:
Answer:
The numbers:
1, -3, 2, -9, 3, -15, 4, -21,
are not linear.
Step-by-step explanation:
If it was linear:
4, 3, 2, 1, -3, -9, -15, -21
