Y intercept: when x = 0
(0, y)
On the graph it is (0,-5)
Solution: y intercept is (0,-5)
Answer:
6n(n³ - 4n² + 3)
Step-by-step explanation:
Given
6
- 24n³ + 18n ← factor out 6n from each term
= 6n(n³ - 4n² + 3) ← which may be factored further if required
The two whole numbers are 5 and 6 ⇒ 3rd answer
Step-by-step explanation:
To prove that a square root number lies between which two consecutive integers do that
- Find a square number less than the number under the root
- Find a square number greater than the number under the root
- Find the square root of the square numbers, they will be the two integers that the root lies between them
∵ The number is
- Find a square number less than 29
∵ 25 is a square number
∵ 25 is less than 29
- Find a square number greater than 29
∵ 36 is a square number
∵ 36 is greater than 29
∴ 25 < 29 < 36
- Take √ for each number
∴
<
<
∵
= 5
∵
= 6
∴ 5 <
< 6
The two whole numbers are 5 and 6
Learn more:
You can learn more about the numbers in brainly.com/question/9621364
#LearnwithBrainly
well, we'll first off put the point AC in component form by simply doing a subtraction of C - A, multiply that by the fraction 2/3, and that result will get added to point A, to get point B.
![\bf \textit{internal division of a segment using a fraction}\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{5})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-4})~\hfill \frac{2}{3}\textit{ of the way from }A\to C \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_2}{4}-\stackrel{x_1}{(-2)}, \stackrel{y_2}{-4}-\stackrel{y_1}{5})\implies (4+2,-9) \stackrel{\textit{component form of segment AC}}{\qquad \implies \qquad (6,-9)} \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Binternal%20division%20of%20a%20segment%20using%20a%20fraction%7D%5C%5C%5C%5C%20A%28%5Cstackrel%7Bx_1%7D%7B-2%7D~%2C~%5Cstackrel%7By_1%7D%7B5%7D%29%5Cqquad%20C%28%5Cstackrel%7Bx_2%7D%7B4%7D~%2C~%5Cstackrel%7By_2%7D%7B-4%7D%29~%5Chfill%20%5Cfrac%7B2%7D%7B3%7D%5Ctextit%7B%20of%20the%20way%20from%20%7DA%5Cto%20C%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%28%5Cstackrel%7Bx_2%7D%7B4%7D-%5Cstackrel%7Bx_1%7D%7B%28-2%29%7D%2C%20%5Cstackrel%7By_2%7D%7B-4%7D-%5Cstackrel%7By_1%7D%7B5%7D%29%5Cimplies%20%284%2B2%2C-9%29%20%5Cstackrel%7B%5Ctextit%7Bcomponent%20form%20of%20segment%20AC%7D%7D%7B%5Cqquad%20%5Cimplies%20%5Cqquad%20%286%2C-9%29%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)

Answer:
I believe the reflection line will be on x=1
Step-by-step explanation:
I tend to eyeball the reflection line to make it symmetrical, if I'm not much of a help I apologize