I think the correct answer is B. It is the triangle case SSA that may have one, two, or zero solutions. This case can have either number of solutions but it depends on the sides of the triangle given. Having one solution can be all of the cases except SSS, having 2 solutions can only be applied to SSA.
X is the number
sum means add
sum of half a number and 4 means
(x/2)+4
result is -16
(x/2)+4=-16
minus 4 both sides
x/2=-20
times 2 both sides
x=-40
the number is -40
Solving by substitution:
y = 4x - 3
2x + 7y = 41
Let us substitute the first equation y = 4x - 3 into the second.
2x + 7y = 41
2x + 7(y = 4x -3) = 41
2x + 7(4x -3) = 41
So that's the third option.
I hope this helps.
1. -6 ≤ x < -1 . . . . conjunction
2. x ≤ 6 . . or . . 10 ≤ x . . . . disjunction
3. 7 ≤ x < 12 . . . . conjunction
4. x < -9 . . or . . -3 ≤ x . . . . disjunction
5. 2 ≤ x ≤ 5 . . . . conjunction
6. x ≤ 54 . . or . . 66 ≤ x . . . . disjunction
7. 39 < x ≤ 43 . . . . conjunction
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Your problem statement provided no letters.
40 percent of 250 = .4*250 = 100
100 seventh graders got the flu.
