Answer: 0.8490
Step-by-step explanation:
Given : The population of lengths of aluminum-coated steel sheets is normally distributed with a mean of 30.0 inches and a standard deviation of 0.9 inches.
i.e.
and 
Let x denotes the lengths of aluminum-coated steel sheets.
Required Formula : 
For n= 36 , the probability that the average length of a sheet is between 29.82 and 30.27 inches long will be :-

∴ Required probability = 0.8490
Each side is about 290mm long
Answer:
tht looks so difficult
Step-by-step explanation:
Answer:
first y then x because y represents 22 and x represents 4 a week.