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dsp73
2 years ago
15

Write the equation of the line parallel to y=1/3x-6 that passes through the point (-12,3) in slope-intercept form.

Mathematics
1 answer:
masha68 [24]2 years ago
4 0

Answer:

y=1/3x+7

Step-by-step explanation:

1. The given equation is y=1/3x-6 and it has to be parallel passing through (-12,3), so you just plug in the x and y values into the equation y=mx+b with 1/3 as the slope since its parallel (meaning the slope is the same for both eqts)

2. 3=1/3(-12)+b

3. 3=-4+b

4. 7=b

5. So, the equation is y=1/3x+7

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