Answer:
Maybe the last one.......
Answer:
c. 61.25 kg
Step-by-step explanation:
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.
a. 15.31 kg
b. 51.40 kg
c. 61.25 kg
d. 80.49 kg
Margin of Error Formula= z × Standard deviation/√n
95% confidence interval = 1.96
Standard deviation = 125kg
n = 16 samples
Margin of error= 1.96 × 125/√16
= 1.96 × 125/4
= 245/4
= 61.25kg
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg
Answer:
0.45
Step-by-step explanation:
Die 1 is loaded so that only 1, 4, and 6 are possible.
P(1) + P(4) + P(6) = 0.5 + 0.25 + 0.25 = 1
Similarly, Die 2 is loaded so that only 2, 3, and 5 are possible.
P(2) + P(3) + P(5) = 1
0.3 + 0.25 + P(5) = 1
P(5) = 0.45
The answer is: "
11 " .
____________________________________________________ → "
x = 11 " .
____________________________________________________Explanation:____________________________________________________Set up the ratio/ proportion as a fraction:
6 cm / 48 cm = 5 cm / (3x + 7) ;
→ The "cm" units cancel out; since: "cm/cm = 1 " ;
→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;
→ Rewrite as:

;
Now, we can "cross-multiply" :
__________________________________________________<u>Note</u>: 
;

;
{b

; d

} .
__________________________________________________ As such:
1 * (3x + 7) = 8 * 5 ;
→ 3x + 7 = 40 ;
Subtract "
7" from each side of the equation:
→ 3x + 7 − 7 = 40 <span>− 7 ;
</span>
to get:
→ 3x = 33 ;
Now, divide each side of the equation by "
3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 33 / 3 ;
to get:
____________________________________________________ → "
x = 11 " .
____________________________________________________ →
The answer is: "
11 " .
____________________________________________________