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Zinaida [17]
3 years ago
12

Which equation has no real solutions?

Mathematics
1 answer:
olasank [31]3 years ago
6 0

Answer:

A

Step-by-step explanation:

x=

−b±√b2−4ac

2a

x=

−(2)±√(2)2−4(2)(15)

2(2)

x=

−2±√−116

4

and there is really no solution

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Step-by-step explanation:

<em>To</em><em> </em><em>attain the</em><em> </em><em>x-intercepts</em><em> </em><em>you</em><em> </em><em>have</em><em> </em><em>to</em><em> </em><em>let</em><em> </em><em>y</em><em> </em><em>=</em><em> </em><em>0</em><em>.</em>

<em>So</em><em> </em><em>in</em><em> </em><em>this</em><em> </em><em>case you will be</em><em> </em><em>having</em><em>:</em>

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<em>4</em><em>x</em><em>/</em><em>4</em><em> </em><em>=</em><em> </em><em>2</em><em>4</em><em>/</em><em>4</em>

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<em>:</em><em>)</em>

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gulaghasi [49]

ABC and AED are congruent by SSS. SSS is if three sides of a triangle are congruent to 3 sides of another triangle, then the triangles are congruent. AB and AE are both 7, BC is congruent to ED and CA is congruent to DA because of the tick marks.

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