The rules are very simple: an angle is acute if it's less than 90°, whereas it is obtuse if it's more than 90°.
So, for the first task, you just need to compare the given angle with 90°. If the angle is less than 90°, it's acute. Otherwise, it's obtuse.
Moving on, angle B is complement of a angle A if A+B=90. So, for example, the complement of the first angle is 80, because 10+80=90. Note that this implies that obtuse angles don't have a complement.
Finally, angle B is supplement of a angle A if A+B=180. So, for example, the complement of the first angle is 170, because 10+170=180.
Answer:
2100
Step-by-step explanation:
LCM of 70, 60, and 50?
First, find the prime factorization of each number.
70 = 2 * 5 * 7
60 = 2^2 * 3 * 5
50 = 2 * 5^2
The LCM is the product of some of the factors above. These are the factors you need to multiply together.
Choose factors that are common with the highest exponent and also factors that are not common.
Common factors: There is a 2, a 2^2, and a 2. Use the 2^2.
There is a 3. Use it.
There is a 5 and a 5^2. Use the 5^2.
There is a 7. Use it.
LCM = 2^2 * 3 * 5^2 * 7
LCM = 2100
Answer: 2100
Answer:
1/2.
Step-by-step explanation:
Let O = an odd number and E an even number.
The possible outcomes for an odd sum are:
OOO
OEE
EOE
EEO
The probability of an odd on each pick = 50/100 = 1/2 and for an even it is also 1/2.
Prob( O O O) = 1/2*1/2*1/2 = 1/8.
The probability for the other 3 possible outcomes is also 1/8 , therefore the probability for odd number totals = 4 * 1/8
= 1/2.
Answer:
Exponential
Step-by-step explanation:
By visual inspection the graph generated by the points plotted is an exponential graph as the graph curves upward. The graph is also continous and differs from either a decreasing or increasing Linear graph, which shows a straight best of fit pattern. Hence, the graph most closely represents an exponential graph from visual examination.
Answer:
Four pack of mangos for 2.76
Step-by-step explanation:
A four pack of mangos is 0.69 per mango while a six pack is
0.72 per mango
