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3 years ago

15

During 30 minutes on the treadmill, LaToya burned 20 calories per minute. What is the rate of change of the function that repres

ents this situation?
0 10 calories per minute
0 20 calories per minute
0 30 calories per minute
0 50 calories per minute

1 answer:

inn [45]3 years ago

4 0

The rate of change is obviously that term that describe the change over a certain period. In this problem, we are given with the condition that LaToya is able to burn 20 calories per minute. Therefore, the rate of change is 20 calories per minute.

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You and five of your friends ordered your tickets online together. JetBlue ticket prices cost $289 round-trip including tax. The

baherus [9]

Answer:

y= 288x + 7.99

Step-by-step explanation:

# of tickets : x

y = 289x + 7.99

⬇️ _________ put in y = mx + b

y = 289(6) + 7.99

⬇️ _________ plug in

y = 1734 + 7.99

⬇️ _________ Add

y = 1741.99

HOPE THIS HELPS! (:

5 0

2 years ago

The distribution of resistance for resistors of a certain type is known to be normal, with 10% of all resistors having a resista

baherus [9]

Answer:

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

10% of all resistors having a resistance exceeding 10.634 ohms

This means that when X = 10.634, Z has a pvalue of 1-0.1 = 0.9. So when X = 10.634, Z = 1.28.

$Z = \frac{X - \mu}{\sigma}$

$1.28 = \frac{10.634 - \mu}{\sigma}$

$10.634 - \mu = 1.28\sigma$

$\mu = 10.634 - 1.28\sigma$

5% having a resistance smaller than 9.7565 ohms.

This means that when X = 9.7565, Z has a pvalue of 0.05. So when X = 9.7565, Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{9.7565 - \mu}{\sigma}$

$9.7565 - \mu = -1.96\sigma$

$\mu = 9.7565 + 1.96\sigma$

We also have that:

$\mu = 10.634 - 1.28\sigma$

So

$10.634 - 1.28\sigma = 9.7565 + 1.96\sigma$

$1.96\sigma + 1.28\sigma = 10.645 - 9.7565$

$3.24\sigma = 0.8885$

$\sigma = \frac{0.8885}{3.24}$

$\sigma = 0.2742$

The mean is

$\mu = 10.634 - 1.28\sigma = 10 - 1.28*0.2742 = 9.65$

The mean is 9.65 ohms and the standard deviation is 0.2742 ohms.

8 0

3 years ago

What is the greatest common factor of 24, 40 and 32? <br> A. 1 <br> B. 2 <br> C. 4 <br> D. 8

trasher [3.6K]

It’s 8 because 24/8 is 3 and 40/8 is 5 and 32/8 is 4 so the answer is 8 YOUR WELCOME

6 0

3 years ago

Read 2 more answers

Help me please!!!!!

g100num [7]

It would be answer choice A (10^5) because there are 5 10s in the problem

7 0

2 years ago

Read 2 more answers

Ava bought 7.73 pounds of fruit for a class party. the class ate 3.59 pounds of the fruit. how much fruit is left?

dem82 [27]

Ava bought $7.73$ pounds of fruit for a class party , class ate $3.59$ pounds fruits then $4.14$ pounds fruit left after party.

How can we find how much fruit is left after party ?

Ava bought $=7.73$ pounds fruit

ate by class $=3.59$ pounds fruit

fruit left after party $= total fruit -fruit ate by class$

$= 7.73-3.59\\=4.14$

So $4.14$ pound fruit is left .

Learn more about the fruit left here :

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6 0

2 years ago