Zeros of this function
- x²-x-6=0
- x²-3x+2x-6=0
- x(x-3)+2(x-3)=0
- (x+2)(x-3)=0
- x={-2,3}
ZEros of reciprocal function
The equation
- x²-(-1/2+1/3)x-(1/2)(1/3)=0
- x²-1/6x-1/6=0
Answer:
(6, - 3 )
Step-by-step explanation:
Given the 2 equations
2x + 5y = - 3 → (1)
2x + 2y = 6 → (2)
Subtracting (1) from (2) term by term will eliminate the x- term
(2x - 2x) + (2y - 5y) = 6 - (- 3), that is
- 3y = 9 ( divide both sides by - 3 )
y = - 3
Substitute y = - 3 in either of the 2 equations and solve for x
Substituting y = - 3 in (1)
2x + 5(- 3) = - 3
2x - 15 = - 3 ( add 15 to both sides )
2x = 12 ( divide both sides by 2 )
x = 6
Solution is (6, - 3 )
Answer:
y=0
Step-by-step explanation:
The asymptote of exponential equations is where is plateaus/flattens out. it will never actually touch it. Here it flattens out on the y-axis.
Answer:
4/7
Step-by-step explanation:
(7/2) m is the width and 18m is the length. This is because area is lxw.let w= width and length=11+2wMultiply together, get 2w^2+11w-63=0factor to get (2w-7)(w+9).Find w and get w=7/2 and w=-9Negative rejected because a measurement can't be negative. Finally substitute that into the length equation (11+2w) to get 18m and width is 7/2 m
