Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
Answer:
224 with a remainder of 9
Answer:
Answer A
Step-by-step explanation:
because formula of a trapezium = (hxbxl) so
(6x8x19) = 912units^3
Answer:
7.2
Step-by-step explanation:
Distance between (4, 3) and (8, 9):
(nearest tenth)
<span>Let the larger number be x.
</span><span>A number, y, is equal to the difference of a larger number and 3.
y = x - 3
x - y = 3
</span>The same number is one-third of the sum of the large number and 9.
y = (1/3)(x + 9)
3y = x + 9
x - 3y = -9
The equations are:
x - y = 3
x - 3y = -9
