Question

Graph the equation h=-16t^2+80. click on the graph until the correct solution appears

Answer 1

Answer:

The graph of the equation h=-16t^2+80 is shown in the figure attached.

The y-intercept is obtained replacing t = 0 in the equation, as follows

h=-16(0)^2+80 = 80

The x-intercepts are obtained replacing h = 0 in the equation, as follows

0=-16t^2+80

16t^2 = 80

t^2 = 80/16

t = √5

t ≈ -2.236 or  t ≈ 2.236

With this 3 points, (0, 80) (-2.236, 0) (2.236, 0)  the curve of a quadratic equation is defined.

Answer 2

The graph of $f(x)=-16 t^{2}+80$ is shown in the graph below.

The graph is of ∩-shape when the constant $a$ of the quadratic equation $a x^{2} +bx+c$ is negative