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2 years ago

What is 4× 10 in standard notation

Mathematics

2 answers:

Nutka1998 [239]2 years ago

8 0

4 × 10×10×10×10×10
4×100000
400000

stiv31 [10]2 years ago

4 0

400000 since you move the decimal 5 places to the right

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THIS IS THE LAST ONE NUMBER 9

Cloud [144]

Answer:(d)

Step-by-step explanation:

Given

AB=AC

$\therefore$ We can write

$\angle ABC=\angle ACB\ \quad \text{[angles corresponding to equal sides are equal]}$

$\angle ABC=\angle BCA=\angle ACB=65^{\circ}$

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2 years ago

Determined the perimeter and area of the following figure. Use 3.14 for pi

nataly862011 [7]

Step-by-step explanation:

first you will put a line in the missing part of the inside of the figure.Once you do you will see that there are two figures.

to find the diagonal of the half-circle : 7cm-2cm-1cm=4cm

Now use the area formulas for each figure.The area of the semicircle is pi×d/2.The area of the rectangle is a×b.

A of semicircle =3.14×4cm/2=6.28cm²

A of rectangle =7×3=21cm²

to find the perimeter of them:

P of semicircle = 3.14×4=12.56cm

P of rectangle =2(7+3)=14+6=20cm

6 0

2 years ago

Find the distance between the points (-5, -4) and (3, 1).

const2013 [10]

Step-by-step explanation:

it will help u

6 0

2 years ago

Witch graph shows a car traveling at 50 mile per hour

Masja [62]

Answer:

I would need to see the graphs to answer this.

5 0

2 years ago

Find the perimeter of rectangle BCEF. Round your answer to the nearest hundredth

777dan777 [17]

Answer:

The perimeter of the rectangle B C E F is 16.97 units

Step-by-step explanation:

* Lets explain how to solve the problem

- B C E F is a rectangle

- The perimeter of the rectangle is the sum of the length of its

four sides

- The coordinates of the vertices of the rectangle are:

B (0 , 3) , C (4 , -1) , E (2 , -3) , F (-2 , 1)

- To find the dimensions of the rectangle use the rule of distance

d = $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

* Lets solve the problem

∵ $(BC)=\sqrt{(4-0)^{2}+(-1-3)^{2}}=\sqrt{16+16}=\sqrt{32}$

∵ $(CE)=\sqrt{(2-4)^{2}+(-3--1)^{2}}=\sqrt{4+4}=\sqrt{8}$

∵ $(FE)=\sqrt{(2--2)^{2}+(-3-1)^{2}}=\sqrt{16+16}=\sqrt{32}$

∵ $(BF)=\sqrt{(-2-0)^{2}+(1-3)^{2}}=\sqrt{4+4}=\sqrt{8}$

∵ The perimeter of the rectangle = BC + CE + FE + BF

∴ The perimeter = $\sqrt{32}+\sqrt{8}+\sqrt{32}+\sqrt{8}=16.97$

∴ The perimeter of the rectangle B C E F is 16.97 units

4 0

3 years ago