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3 years ago

What is 4× 10 in standard notation

Mathematics

2 answers:

Nutka1998 [239]3 years ago

8 0

4 × 10×10×10×10×10
4×100000
400000

stiv31 [10]3 years ago

4 0

400000 since you move the decimal 5 places to the right

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Write an equation and solve each problem.

Oksi-84 [34.3K]

Answer:

x-8=37

37+8=x

45=x

45 is your answer

Step-by-step explanation:

7 0

3 years ago

The population of a species is modeled by the equation p(t)=-t^4+72t^2+225, where t is the number of years. find the approximate

Shtirlitz [24]

Answer:

The approximate number of years until the species is extinct will be 9 years

Step-by-step explanation:

We are given

The population of a species is modeled by the equation

$p(t)=-t^4+72t^2+225$

where

t is the number of years

we have to find time when species extinct

we know that any species will be extinct only if population of that species becomes 0

so, we can set P(t)=0

and then we can solve for t

$p(t)=-t^4+72t^2+225=0$

we can factor it

$(t^2+3)(t^2-75)=0$

$(t^2+3)=0$

we get t value as imaginary for this equation

$(t^2-75)=0$

$t=\sqrt{75}$

$t=8.660$

So,

the approximate number of years until the species is extinct will be 9 years

8 0

4 years ago

Evaluate the expression.<br><br> 2^3=___

victus00 [196]

2^3=2*2*2=4*2=8
the answer is 8

7 0

3 years ago

An equivalent equation for 4x+11=15

Keith_Richards [23]

Answer:I can solve it?

take away 11 from both sides to make..

4x = 4

simplified (4 ÷ 4) to make x=1

Step-by-step explanation:

4 0

4 years ago

An equilateral triangle is inscribed in a circle of radius 6r. Express the area A within the circle but outside the triangle as

Paul [167]

Answer:

$A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$

Step-by-step explanation:

We have been given that an equilateral triangle is inscribed in a circle of radius 6r. We are asked to express the area A within the circle but outside the triangle as a function of the length 5x of the side of the triangle.

We know that the relation between radius (R) of circumscribing circle to the side (a) of inscribed equilateral triangle is $\frac{a}{\sqrt{3}}=R$ .

Upon substituting our given values, we will get:

$\frac{5x}{\sqrt{3}}=6r$

Let us solve for r.

$r=\frac{5x}{6\sqrt{3}}$

$\text{Area of circle}=\pi(6r)^2=\pi(6\cdot \frac{5x}{6\sqrt{3}})^2=\pi(\frac{5x}{\sqrt{3}})^2=\frac{25\pi x^2}{3}$

We know that area of an equilateral triangle is equal to $\frac{\sqrt{3}}{4}s^2$ , where s represents side length of triangle.

$\text{Area of equilateral triangle}=\frac{\sqrt{3}}{4}s^2=\frac{\sqrt{3}}{4}(5x)^2=\frac{25\sqrt{3}}{4}x^2$

The area within circle and outside the triangle would be difference of area of circle and triangle as:

$A(x)=\frac{25\pi x^2}{3}-\frac{25\sqrt{3}x^2}{4}$

We can make a common denominator as:

$A(x)=\frac{4\cdot 25\pi x^2}{12}-\frac{3\cdot 25\sqrt{3}x^2}{12}$

$A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$

Therefore, our required expression would be $A(x)=\frac{100\pi x^2-75\sqrt{3}x^2}{12}$ .

7 0

3 years ago