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3 years ago

For thermometers to read temperatures correctly they must be

2 answers:

8 0

For thermometers to read temperatures correctly, they must be immersed in the substance being measured while reading the temperature. When they are taken out the substance, there is a possibility that the fluid inside would change its level due to the sudden change in the temperature. Thus, giving you an erroneous reading of the temperature.

charle [14.2K]3 years ago

5 0

For the measurement of the temperatures correctly the thermometers Should Fully dipped into Fluids So that it is dipped into the Fluids and give you Correct reading.

Further Explanation:

Explanation:

First of all we should check that the liquid in the thermometer should be at below the room temperature. If it is not below this temperature please bring its temperature below the room temperature by shaking the thermometer.

When the temperature below the room Temperature:

When the Temperature of the thermometer is below the room temperature then dipped the thermometer into the fluid of which you have to checked the temperature. Make sure that the Thermometer dipped into the fluid properly.

Difficulties:

If thermometer is not dipped properly in the fluid then the temperature of fluid should not be measured correctly an there should be an error in the measurement.

When you take off the thermometer from the fluid then the Liquid in the thermometer can be leveled down because of sudden change of Temperature of the temperature of fluid to the room Temperature.

Answer Details:

Subject: Physics

Level: High School.

Key Words:

Explanation:

When the temperature below the room Temperature:

Difficulties:

For further Evaluation:

brainly.com/question/6362387

brainly.com/question/12938965

brainly.com/question/1759515

brainly.com/question/4819550

thanks

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A mass weighing pounds is attached to a spring whose constant is lb/ft. The medium offers a damping force that is numerically eq

andreyandreev [35.5K]

Answer:

hello your question has some missing values attached below is the complete question with the missing values

answer :

a) 0.083 secs

b) 0.33 secs

c) 3e^-4/3

Explanation:

Given that

g = 32 ft/s^2 , spring constant ( k ) = 2 Ib/ft

initial displacement = 1 ft above equilibrium

mass = weight / g = 4/32 = 1/8

damping force = instanteous velocity hence β = 1

a)Calculate the time at which the mass passes through the equilibrium position.

time mass passes through equilibrium = 1/12 seconds = 0.083

b) Calculate the time at which the mass attains its extreme displacement

time when mass attains extreme displacement = 1/3 seconds = 0.33 secs

c) What is the position of the mass at this instant

position = 3e^-4/3

attached below is the detailed solution to the given problem

6 0

3 years ago

If an electron moves in a circle of radius 21 cm perpendicular to a B field of 0.4 T, what are the speed of the electron and the

kodGreya [7K]

Answer:

$v = 4.048 *10^6$ m/s

Angular frequency = $1.92 * 10^7$

Explanation:

As we know

$v = \frac{qBr}{m}$

q is the charge on the electron = $3.2 * 10^{-19}$ C

B is the magnetic field in Tesla = $0.4$ T

r is the radius of the circle = $0.21$ m

mass of the electrons = $6.64 * 10^{-27}$ Kg

Substituting the given values in above equation, we get -

$v = \frac{3.2 * 10^{-19}*0.4*0.21}{6.64 * 10^{-27}} \\v = 4.048 *10^6$ m/s

Angular frequency =

$\frac{4.048 * 10^6 }{0.21} \\1.92 * 10^7$

8 0

3 years ago

If the coefficient of kinetic friction between tires and dry pavement is 0.84, what is the shortest distance in which you can st

liberstina [14]

Answer:

The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

Explanation:

Given;

coefficient of kinetic friction, μ = 0.84

speed of the automobile, u = 29.0 m/s

To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;

v² = u² + 2ax

where;

v is the final velocity

u is the initial velocity

a is the acceleration

x is the shortest distance

First we determine a;

From Newton's second law of motion

∑F = ma

F is the kinetic friction that opposes the motion of the car

-Fk = ma

but, -Fk = -μN

-μN = ma

-μmg = ma

-μg = a

- 0.8 x 9.8 = a

-7.84 m/s² = a

Now, substitute in the value of a in the equation above

v² = u² + 2ax

when the automobile stops, the final velocity, v = 0

0 = 29² + 2(-7.84)x

0 = 841 - 15.68x

15.68x = 841

x = 841 / 15.68

x = 53.64 m

Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m

4 0

3 years ago

How to reduce friction of moving a heavy load .

Vilka [71]

● Use lubricants such as oil.
● Place the load on a piece of cloth as it can ease the friction
● Place the load on a cart with wheels so it can be converted to rolling friction and can be pushed easily.
● Place the load on an inclined plane

3 0

4 years ago

A projectile is launched horizontally from the top a 35.2m high cliff and lands a distance of 107.6m from the base of the cliff.

tankabanditka [31]

Answer:

$v_o=40.14\ m/s$

Explanation:

Horizontal Launch

It happens when an object is launched with an angle of zero respect to the horizontal reference. It's characteristics are:

The horizontal speed is constant and equal to the initial speed $v_o$
The vertical speed is zero at launch time, but increases as the object starts to fall
The height of the object gradually decreases until it hits the ground
The horizontal distance where the object lands is called the range

We have the following formulas

$\displaystyle v_x=v_o$

$\displaystyle x=v_o.t$

$\displaystyle v_y=g.t$

$\displaystyle y=\frac{gt^2}{2}$

Where $v_o$ is the initial horizontal speed, $v_y$ is the vertical speed, t is the time, g is the acceleration of gravity, x is the horizontal distance, and y is the height.