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skad [1K]
3 years ago
14

_____ analyzes the interaction of low-frequency sound waves with tissues to create moving images of internal organs.

Physics
1 answer:
Degger [83]3 years ago
4 0

Answer: Ultrasound

Explanation:

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What is a reasonable estimate of the average kinetic energy of an athlete during a 100 m race that takes 10s?
arlik [135]
The average weight of an athlete should be around 60kg so from the information that the athlete can run 100m in 10s, we can calculate that their average speed is 10m/s. Using the kinetic energy formula, Ek = 1/2mv^2 we can calculate the kinetic energy using 60kg as the mass.

(1/2)(60)(10^2) = Ek

Ek= 3000J
7 0
3 years ago
Height of a low earth orbit?
Darya [45]
I used google but 2000km
7 0
3 years ago
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A 0.45 kg ball is moving horizontally with a speed of 5.3 m/s when it strikes a vertical wall. The ball rebounds with a speed of
qaws [65]

Answer:

1.31Kgms-1

Explanation:

∆p = m∆v

Where:

∆p= change in momentum

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Therefore, substituting appropriately with the values above:

∆p= 0.45×2.9= 1.31Kgms-1

6 0
4 years ago
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Two technicians are discussing the testing of a catalytic converter. Technician A says that a vacuum gauge can be used and obser
Andrej [43]

Answer:

Answer is C. Both technicians A and B.

Refer below.

Explanation:

Two technicians are discussing the testing of a catalytic converter. Technician A says that a vacuum gauge can be used and observed to see if the vacuum drops with the engine at 2500 RPM for 30 seconds. Technician B says that a pressure gauge can be used to check for backpressure. The following technician is correct:

Both technicians A and B

7 0
3 years ago
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Please help! If the instantaneous speed of an object remains constant, can its instantaneous velocity change? If the instantaneo
kondaur [170]
<span>
I think the the answer would be no. </span> If the instantaneous speed of an object remains constant, then its instantaneous velocity would not change. S<span>ince v = c for c is some constant, then |v| = |c|. This is regardless of the sign of c. Hope this answers the question.</span>
4 0
4 years ago
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