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Studentka2010 [4]
3 years ago
14

Use the image to answer the question. (Please help thank you.)

Physics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Gravity all the time.

Also friction whenever it's moving.

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How can having a mentor help individuals achieve their goals? A. Mentors can increase accountability. B. Mentors can increase mo
lana [24]

Your best bet is to go with D.

6 0
3 years ago
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How can one tell if an object can absorb light or not? How about transmit?<br> Thank you!
kondaur [170]

<u>Absorb:</u>
Shine a light with known intensity into the object. 
Measure the intensity of the light that comes out.
Any light that goes in but doesn't come out the other side
   was absorbed by the object.
(Note:  You also need to be aware of any light that bounces back from
the first side without entering the object.  That light is <em><u>reflected</u></em> from it,
and can't be expected to show up at the other side.)

<u>Transmit:</u>
Any light that goes in and DOES come out the other side
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4 0
3 years ago
The liquid pressure varies with depth why​
Solnce55 [7]

Explanation:

Hey, there!

The liquid pressure varies with depth because liquid pressure is directly proportional to the depth of liquid from the free surface of the liquid. so, more the depth more the pressure and less the depth less the pressure.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

3 0
4 years ago
Reactance Frequency Dependence: Sketch a graph of the frequency dependence of a resistor, capacitor, and inductor. RLC Circuit R
jolli1 [7]

Answer:

f=\frac{1}{2\pi \sqrt{LC}}

Explanation:

We know that impedance of a RLC circuit is given by Z=R+J(X_L-X_C)

So Z=\sqrt{R^2+(X_L-X_C)^2} here R is resistance X_L is inductive reactance and X_C is capacitive reactance

To minimize the impedance X_L-X_C should be zero we know that X_L=\omega L\ and \ X_C=\frac{1}{\omega C}

So \omega L-\frac{1}{\omega C}=0

\omega ^2=\frac{1}{LC}

\omega =\sqrt{\frac{1}{LC}}

We know that \omega =2\pi f

So \omega =2\pi f=\frac{1}{\sqrt{LC}}

f=\frac{1}{2\pi \sqrt{LC}}

Where f is resonance frequency  

8 0
3 years ago
You set a small eraser at a distance of 0.27 m from the center of a turntable you find in the attic and establish that when the
Licemer1 [7]

Answer with Explanation:

We are given that

Distance,r=0.27 m

Tangential speed=v=0.49 m/s

a.Angular speed ,\omega=\frac{v}{r}

Using the formula

\omega=\frac{0.49}{0.27}=1.8 rad/s

\omega=\frac{2\pi}{T}

T=\frac{2\pi}{\omega}

Time period,T=\frac{2\pi}{1.8}=3.49 s

b.Amplitude,A=Distance of small eraser from the center of a turnable =0.27 m

c.Maximum speed,V_{max}=0.49 m/s

d.Maximum acceleration=a=r\omega^2=0.27(1.8)^2=0.87 m/s^2

5 0
4 years ago
Read 2 more answers
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