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Fudgin [204]
3 years ago
12

If a charge travels through a magnetic field, it experiences a magnetic force and its velocity is perpendicular to the direction

of the magnetic field. Answer the following questions about the situations given below.
What is the direction of the force on a positive charge when passing through a magnetic field as indicated in the diagram? Explain how you got your answer.
+q ->(right arrow) v (downwards arrow)B

What is the direction of the magnetic field above and below the current-carrying wire below, where the current is flowing in the +x- direction? Explain how you got your answer
[image of a long arrow pointing to the right]

Why aren't the right-hand rules used to figure out the force exerted on particles traveling parallel to a magnetic field?​
Physics
1 answer:
Oduvanchick [21]3 years ago
4 0

Answer:

cant see

Explanation:

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A satellite is a moon, planet or machine that orbits a planet or star.
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A child is riding a merry-go-round, which has an instantaneous angular speed of 1.25 rad/s and an angular acceleration of 0.745
Elena L [17]

w = instantaneous angular speed = 1.25 rad/s

r = radius = 4.65 m

α = angular acceleration = 0.745 rad/s²

centripetal acceleration is given as

a_{c} = rw²

a_{c} = (4.65 ) (1.25)² = 7.27 m/s²

tangential acceleration is given as

a_{t} = rα

a_{t} =4.65 x 0.745 = 3.46 m/s²

angle is given as

\theta = tan^{-1}(\frac{a_{c}}{a_{t}})

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3 years ago
Two carts on a straight track collide head on. The first cart was moving at 3.6 m/s in the positive x direction and the second w
zubka84 [21]

Answer:

vf₁  = -7.2 m/s :  The first car moves in the negative x direction after the collision.

Explanation:

Theory of collisions  

Linear momentum is a vector magnitude (same direction of the velocity) and its magnitude is calculated like this:  

p=m*v  

where  

p:Linear momentum  

m: mass  

v:velocity  

There are 3 cases of collisions : elastic, inelastic and plastic.  

For the three cases the total linear momentum quantity is conserved:  

P₀ = Pf   Formula (1)  

P₀ :Initial linear momentum quantity  

Pf : Final linear momentum quantity  

Data

m₁ = m kg : mass of the first car

m₂= 5m kg : mass of the second car

v₀₁ = 3.6 m/s : Initial velocity of m₁  , to the +x axis :

v₀₂= -2.4 m/s m/s : Initial velocity of m₂ ,  to the -x axis

vf₂= -0.24 m/s m/s : Final velocity of m₂ ,  to the -x axis

Problem development

We appy the formula (1):

P₀ = Pf  

m₁*v₀₁ + m₂*v₀₂ = m₁*vf₁ + m₂*vf₂  

We assume that the first car moves in the positive x direction after the collision., so, the sign of the final speeds is positive:

(m)*( 3.6) + (5m)*( -2.4) = (m)*vf₁ +(5m)*(- 0.24)

3.6m  - 12m=  m*vf₁ - 1.2m

We divided by m both sides of the equation

3.6 - 12= vf₁ -1.2

3.6 - 12 +1.2 = vf₁

-7.2  = vf₁

vf₁  = -7.2 m/s  : The first car moves in the negative x direction after the collision.

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