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UNO [17]
2 years ago
9

Please I need your help

Physics
1 answer:
frez [133]2 years ago
5 0
1.14 km = Distance
2.30 m/s = Speed
5.12 cm/s2 = Speed
6.150 mph = Distance
8.3.2 sec = Speed
9.25 ft = Distance
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What is the frequency of a wave that has a period of vibration of 2 seconds?
34kurt

Answer:

The answer is 0.5 Hz

Explanation:

Its pretty easy to get the answer. One hertz (Hz) is equal to one cycle or period per second. So, just divide the period by the number of seconds.

1 period/2 secs = 1/2 Hz or 0.5 Hz

7 0
2 years ago
An electric model train is accelerated at a rate of 8 m/s^2 by a 12 N force? What is the
jok3333 [9.3K]

Answer:

m = 1.5 kg

Explanation:

Data:

  • Aceleration (a) = 8 m/s²
  • Force (F) = 12 N
  • Mass (m) = ?

Use formula:

  • \boxed{m = \frac{F}{a}}

Replace in the formula:

  • \boxed{m = \frac{12N}{8\frac{m}{s^{2}}}}

Equate the newtons:

  • \boxed{m = \frac{12kg*\frac{m}{s^{2}}}{8\frac{m}{s^{2}}}}

Simplify m/s²:

  • \boxed{m = \frac{12kg}{8}}

It divides:

  • \boxed{m =1.5kg}

What is the mass of the train?

The mass of the train is <u>1.5 kilograms.</u>

4 0
2 years ago
A heated iron is pressed against a shirt, warming it. This is an
Nady [450]

Answer:

Convection? I'm pretty sure that's it

6 0
2 years ago
This experiment deals with the relationship between volume and temperature for a fixed amount of gas at constant pressure. Desig
creativ13 [48]

Your experiment should keep one thing constant and measure the other. So vary the temp and measure the pressure. You will get a set of data that relates pressure with temp.
<span>PV = nRT
So
P and T are directly proportional.
</span>These experiments are one of either Boyle-Mariottte's, Gay-Lussac'a or Charles' law.

8 0
3 years ago
Two loudspeakers emit sound waves along the x-axis. The sound has maximum intensity when the speakers are 19 cm apart. The sound
Roman55 [17]

Answer:

a.96cm

b.77cm

Explanation:

Highest intensity,d_1=19cm

Lowest intensity,d_2=29cm

d_1+d_2=19+29=48cm  

48cm is the distance for half-wave, wavelength =48cm*2=96cm

b. From a, above we know that half-wavelength is 48cm

Also, the distance of known  maximum is 29cm

Next maximum is calculated as:

Next \m\aximum=Last \ Maximum+ \ 0.5Wavelength\\=29cm+48cm\\=77cm

The next maximum will occur at 77cm

6 0
3 years ago
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