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Masja [62]
3 years ago
8

An unfortunate astronaut loses his grip during a spacewalk and finds himself floating away from the space station, carrying only

a rope and a bag of tools. First he tries to throw a rope to his fellow astronaut, but the rope is too short. In a last ditch effort, the astronaut throws his bag of tools in the direction of his motion, away from the space station. The astronaut has a mass of m a = 124 kg and the bag of tools has a mass of m b = 13.0 kg. If the astronaut is moving away from the space station at v i = 2.10 m / s initially, what is the minimum final speed v b , f of the bag of tools with respect to the space station that will keep the astronaut from drifting away forever?
Physics
1 answer:
Pavel [41]3 years ago
4 0

Answer:

vb = 22.13 m/s

Explanation:

ma = 124 kg

mb = 13 kg

vi = 2.10 m/s

According to the property of conservation of momentum, and considering that, initially, both the astronaut and the bag moved together at 2.10 m/s:

(m_a+m_b)v_i=m_av_a+m_bv_b

The minimum final velocity of the bag, vb, the will keep the astronaut from drifting away forever occurs when va = 0:

(124+13)2.10=124*0+13v_b\\v_b=\frac{287.7}{13}\\v_b= 22.13\ m/s

The minimum final velocity of the bag is 22.13 m/s.

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A 3.00N rock is thrown vertically into the air from the ground. At h=15.0m, v=25m/s upward. Use the work-energy theorem to find
butalik [34]

Answer:

so initial speed of the rock is 30.32 m/s

correct answer is b. 30.3 m/s

Explanation:

given data

h = 15.0m

v = 25m/s

weight of the rock m = 3.00N  

solution

we use here work-energy theorem that is express as here

work = change in the kinetic energy    ..............................1

so it can be written as

work = force × distance     ...................2

and

KE is express as

K.E = 0.5 × m × v²  

and it can be written as

F × d = 0.5 × m × (vf)² - (vi)²      ......................3

here

m is mass and vi and vf is initial and final velocity

F = mg = m  (-9.8)  , d = 15 m and v{f} = 25 m/s

so put value in equation 3 we get

m  (-9.8) × 15 = 0.5 × m × (25)² - (vi)²

solve it we get

(vi)² =  919

vi = 30.32 m/s

so initial speed of the rock is 30.32 m/s

5 0
3 years ago
A football player with a mass of 85 kg wears a uniform and helmet that have a mass of 4.5 kg. The football player moves at 2.1 m
DochEvi [55]
The answer would be 187.95 kg.m/s.

To get the momentum, all you have to do is multiply the mass of the moving object by the velocity. 

p = mv

Where:
P = momentum
m = mass
v = velocity

Not the question is asking what is the total momentum of the football player and uniform. So we need to first get the combined mass of the football player and the uniform. 

Mass of football player = 85.0 kg
Mass of the uniform     = <u>  4.5 kg</u>
TOTAL MASS                  89.5 kg

So now we have the mass. So let us get the momentum of the combined masses. 

p = mv
   = (89.5kg)(2.1m/s)
   = 187.95 kg.m/s

5 0
3 years ago
Read 2 more answers
A) About 9.1<br> B) about 14.1<br> C) about 17.2<br> D) about 18.1 <br><br> Please help me
Mnenie [13.5K]

D. 18.1

K^+H^+G^=180° (sum of int angles of triangle)

K^+30+62=180

K^=88°

GH/sinK=KG/sinH

X/sin88=16/sin62

X*sin62/sin62=16*sin88/sin62

X=18.1

8 0
3 years ago
Please help help help help help<br><br>I will give brainlist and I will follow you​
Feliz [49]

Answer:

1st One (The tendency of objects to keep doing what they are doing)

Explanation:

Inertia is simply the tendency of an object to keep on doing whatever it is doing. It is the natural tendency of an object to stubbornly maintain its state of motion.

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7 0
2 years ago
A thin, horizontal rod with length l and mass M pivots about a vertical axis at one end. A force with constant magnitude F is ap
katen-ka-za [31]

Answer:

The magnitude of the angular acceleration is α = (3 * F)/(M * L)

Explanation:

using the equation of torque to the bar on the pivot, we have to:

τ = I * α, where

I = moment of inertia

α = angular acceleration

τ = torque

The moment of inertia is equal to:

I = (M * L^2)/3

Also torque is equal to:

τ = F * L

Replacing:

I * α = F * L

α = (F * L)/I = (F * L)/((M * L^2)/3) = (3 * F)/(M * L)

8 0
3 years ago
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