Let the price of a ticket be originally T dollars, and the number of clients be N.
let the price decrease by x 3-dollars.
"there is an average increase of 4 people for every $3 decrease on the price of the ticket."
means:
if the price is decreased by 1-3$:
then N become N+4, and T becomes T-3
if the price is decreased by 2-3$:
then N become N+4+4=N+2*4, and T becomes T-3-3=T-2*3
So if the price is decrease by x-3 dollars:
N becomes N+4x, and T becomes T-3x
"A circus owner sells an average of 340 tickets when the price of a ticket is $75."
In this case N=340, and T=75$
If the owner does not change the price ticket, x=0, the revenue is 340*75,
If the owner decreases the price of the tickets by x-3$, then the revenue will be
(N+4x)(T-3x)=(340+4x)(75-3x) dollars,
If R is the function of the revenue depending on x, then
R(x)=(340+4x)(75-3x) dollars
Answer: R(x)=(340+4x)(75-3x) dollars
Answer:
yes
Step-by-step explanation:
(5_3)^2+2(0)=4
substitute with the 5 to x and 0 to y
Answer:
3 = x
Step-by-step explanation:
0 > 3x - 3 - 6
You want to group up the -3 and -6 first
0 > 3x - 9
Then you want to add 9 to each side to cancel out the negative 9 on one side.
0 > 3x - 9
+9 +9
9 > 3x
Now you just divide by 3 on each side
3 = x
Answer:
6/10
Step-by-step explanation:
2 × 3 = 6
5 × 2 = 10
OR
6/10 = 3/5
