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labwork [276]
3 years ago
8

What is the average of 79.3, 64.3, 103.4, 46.4, 46.2

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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Pls help its for my final
ASHA 777 [7]
3.16227766017 because I did the math and yea I think that’s correct
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3 years ago
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Solve the inequality<br> -1/3h ≥ 7<br> A. h ≥ –21<br> B. h ≤ 7 1/3<br> C. h ≤ –21<br> D. h ≥ -2 1/3
JulsSmile [24]
The Answer Is C Fam...................
8 0
3 years ago
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Oblicz.Pamiętaj o kolejności wykonywania działań
SashulF [63]

Answer:

33.275

Step-by-step explanation:

<u>1 step:</u> Difference in brackets

3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}

<u>2 step:</u> 0.75\div\dfrac{1}{3}

0.75\div\dfrac{1}{3}=\dfrac{75}{100}\div \dfrac{1}{3}=\dfrac{3}{4}\times \dfrac{3}{1}=\dfrac{9}{4}

<u>3 step:</u> 1.28\div 0.04

1.28\div 0.04=128\div 4=32 \ \text{Move point two decimal places}

<u>4 step:</u>

2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}

<u>5 step:</u>

\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275

6 0
2 years ago
Solve the inequality.<br> 4│x + 5│ - 2 ≤ 10
castortr0y [4]

Step-by-step explanation: To solve this absolute value inequality,

our goal is to get the absolute value by itself on one side of the inequality.

So start by adding 2 to both sides and we have 4|x + 5| ≤ 12.

Now divide both sides by 3 and we have |x + 5| ≤ 3.

Now the the absolute value is isolated, we can split this up.

The first inequality will look exactly like the one

we have right now except for the absolute value.

For the second one, we flip the sign and change the 3 to a negative.

So we have x + 5 ≤ 3 or x + 5 ≥ -3.

Solving each inequality from here, we have x ≤ -2 or x ≥ -8.

6 0
2 years ago
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Convert the polar representation of this complex number into its standard form z=4(cos150+isin150).
Katen [24]

Answer:

B

Step-by-step explanation:

Using the exact values

cos150° = - cos30° = - \frac{\sqrt{3} }{2}

sin150° = sin30° = \frac{1}{2}

Given

z = 4(cos150° + isin150° ) , substitute values

  = 4(- \frac{\sqrt{3} }{2} +  \frac{1}{2}i )

  = - 2\sqrt{3} + 2i , that is

(- 2\sqrt{3}, 2 ) → B

7 0
3 years ago
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