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nexus9112 [7]
3 years ago
8

The study of all chemicals containing carbon

Chemistry
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

Organic chemistry

Explanation:

laila [671]3 years ago
6 0
The correct answer is 
<span>3. Organic Chemistry.....</span>
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If the following elements were to combine with each other, choose which demonstrate the Law of Multiple Proportion. Select all t
Ilia_Sergeevich [38]

Missing question: Z:X = 7:1 A:Z = 2.5:1 A:Z = 2.2:1 Y:X = 11:1.

Answer is:<span> Z:X = 7:1 and Y:X = 11:1.
Law of multiple proportions or Dalton's Law said that the ratios of the masses of the second element which combine with a fixed mass of the first element will be ratios of small whole numbers. 
In this example ratios are whole numbers, A:Z = 2.5 : 1 and A:Z = 2.2 : 1 are not whole number ratios.</span>

3 0
3 years ago
An aqueous potassium carbonate solution is made by dissolving 5.51 moles of K 2 CO 3 in sufficient water so that the final volum
ad-work [718]

Answer:

1.67mol/L

Explanation:

Data obtained from the question include:

Mole of solute (K2CO3) = 5.51 moles

Volume of solution = 3.30 L

Molarity =?

Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:

Molarity = mole of solute /Volume of solution

Molarity = 5.51 mol/3.30 L

Molarity = 1.67mol/L

Therefore, the molarity of K2CO3 is 1.67mol/L

3 0
3 years ago
Read 2 more answers
Under the right conditions aluminum will react with chlorine to produce aluminum chloride.
salantis [7]

Answer:

m_{Al}=9.42gAl

Explanation:

Hello there!

In this case, according to the given chemical reaction:

2 Al + 3 Cl2 --> 2 AlCl3

Whereas there is a 2:3 mole ratio of aluminum to chlorine; it will be possible for us to calculate the required grams of aluminum by using the equality 22.4 L = 1 mol, the aforementioned mole ratio and the atomic mass of aluminum (27.0 g/mol) to obtain:

m_{Al}=11.727LCl_2*\frac{1molCl_2}{22.4LCl_2}*\frac{2molAl}{3molCl_2}  *\frac{27.0gAl}{1molAl} \\\\m_{Al}=9.42gAl

Regards!

8 0
3 years ago
Why are the oxidation and reduction half-reactions separated in an<br> electrochemical cell?
Aleksandr [31]

Answer:

<h2>It makes the current viable enough to pass through an exterior wire.</h2>

Explanation:

Electrochemical cells primarily comprise of two half-cells. These half-cells assist in isolating the oxidation and reduction half-reactions. These two reactions are linked by a wire which allows the current to move from one edge to the other. The oxidation at the anode and the reduction take place at the cathode and the addition of a salt bridge helps in completing the circuit and permits the current to flow and leads to the generation of electricity.

7 0
3 years ago
A 15.0 L tank of gas is contained at a high pressure of 8.20 x 10^4 torr. The tank is opened and the gas expands into an empty c
Inga [223]

Answer:

20.5torr

Explanation:

Given parameters:

V₁  = 15L

P₁  = 8.2 x 10⁴torr

V₂ = 6 x 10⁴L

Unknown:

P₂  = ?

Solution:

To solve this problem we have to apply the claims of Boyle's law.

Boyle's law is given mathematically as;

            P₁ V₁   = P₂V₂

where P₁ is the initial pressure

          V₁ is the initial volume

           P₂ is final pressure

           V₂ is final volume

   8.2 x 10⁴  x 15  = P₂  x 6 x 10⁴

         P₂  = 20.5torr

5 0
3 years ago
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