Complete the mechanism for the cleavage of the ether by adding any missing atoms, bonds, charges, nonbonding electrons, and curv
ed arrows.
1 answer:
This reaction is known as Acidic Cleavage of Ether. Ether when treated with strong acid like HI, the oxygen atom of ether picks the proton making a positive charge on oxygen. The Iodide conjugate base formed acts as a nucleophile and attacks on the carbon next to positive oxygen and forms Alkyl Halide. This is a type of SN² reaction. The complete reaction with missing atoms, charges and arrows is shown below,
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Answer : The mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.
Explanation : Given,
Vapor presume of 1‑Propanol = 20.9 torr
Vapor presume of 2‑Propanol = 45.2 torr
Mole fraction of 1‑Propanol = 0.540
Mole fraction of 2‑Propanol = 1-0.540 = 0.46
First we have to calculate the partial pressure of 1‑Propanol and 2‑Propanol.
where,
= partial vapor pressure of 1‑Propanol
= vapor pressure of pure substance 1‑Propanol
= mole fraction of 1‑Propanol
and,
where,
= partial vapor pressure of 2‑Propanol
= vapor pressure of pure substance 2‑Propanol
= mole fraction of 2‑Propanol
Thus, total pressure = 11.3 + 20.8 = 32.1 torr
Now we have to calculate the mole fraction of vapor phase 1‑Propanol and 2‑Propanol.
and,
Thus, the mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.