Question

1. Sodium hydroxide reacts with carbon dioxide according to the equation: 2NaOH(s) + CO2(g) →

Answer 1

The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH

What is Limiting reagent ?

The limiting reactant (or limiting reagent) is the reactant that gets consumed first in a chemical reaction and therefore limits how much product can be formed.

Given chemical equation in balanced form ;

2NaOH(s) + CO₂(g) → Na₂CO₃(s) + H₂O(l).

According to the Chemical equation ;

• The limiting reagent when 5 g of NaOH and 4.4 g CO₂  allowed to react will be NaOH
  
  If 44 g CO₂ requires 80 g of NaOH, therefore, 4.4 g CO₂ will require atleast 8 g of NaOH.
  
  But the available quantity is 5 g NaOH. thus, NaOH is the Limiting reagent.
  
  
• 6.625 g of Na₂CO₃ are expected to be produced 5.0 g of NaOH and 4.4 g of CO₂ are allowed to react
  
  As 80 g NaOH produces 106 g of Na₂CO₃.
  
  Therefore 5 g NaoH will produce ;
  
  106 / 80 x 5 = 6.625 g

Learn more about limiting reagent here ;

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