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lutik1710 [3]
2 years ago
7

Cuál es la importancia de una fórmula química y explique las clases de fórmulas con sus ejemplos respectivos.

Chemistry
1 answer:
Ksenya-84 [330]2 years ago
8 0

Answer and Explanation:

Las fórmulas químicas sirven para conocer qué elementos químicos y en qué cantidad están presentes en un compuesto químico. Por ejemplo: la fórmula química del dióxido de carbono es CO₂. Esta fórmula nos indica que la molécula de dióxido de carbono está formada por 1 átomo del elemento químico carbono y 2 átomos del elemento oxígeno.

Los diferentes tipos de fórmulas químicas son: fórmula empírica, fórmula molecular, fórmula semi-desarrollada y fórmula desarrollada. Tomando como ejemplo al compuesto <em>butano</em>:

- Fórmula empírica: C₂H₅ (indica que hay 2 átomos de C por cada 5 átomos de H; es una fórmula mínima)

- Fórmula molecular: C₄H₁₀ (indica que en realidad cada molécula de butano tiene 4 átomos de C y 10 átomos de H).

- Fórmula semi-desarrollada: CH₃CH₂CH₂CH₃ (indica el órden en que se unen los átomos en la molécula).

-Fórmula desarrollada: ver dibujo adjunto (indica cómo están unidos los átomos dentro de la molécula. Ahora vemos los enlaces entre los átomos y que los 2 átomos de C de los extremos están unidos a 3 átomos de H y a otro C, y los dos átomos de C del medio están unidos cada uno a 2 C y 2 H).

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A 0.753 g sample of a monoprotic acid is dissolved in water and titrated with 0.250 M NaOH. What is the molar mass of the acid i
Alexeev081 [22]

Answer:

MM_{acid}=140.1g/mol

Explanation:

Hello,

In this case, since the acid is monoprotic, we can notice a 1:1 molar ratio between, therefore, for the titration at the equivalence point, we have:

n_{acid}=n_{base} \\\\V_{acid}M_{acid}=V_{base}M_{base}\\\\n_{acid}=V_{base}M_{base}

Thus, solving for the moles of the acid, we obtain:

n_{acid}=0.0215L*0.250\frac{mol}{L}=5.375x10^{-3}mol

Then, by using the mass of the acid, we compute its molar mass:

MM_{acid}=\frac{0.753g}{5.375x10^{-5}mol} \\\\MM_{acid}=140.1g/mol

Regards.

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