Suppose the number is x, its reciprocal is 1/x
x+1/x=13/6
(x^2+1)/x=13/6
6(x^2+1)=13x
6x^2-13x+6=0
(3x-2)(2x-3)=0
x=2/3 or x=3/2
Answer:
9.6
2.4.
Step-by-step explanation:
It is easy. If you do with calculator it's easy.
Answer:
D
Step-by-step explanation:
2y=10x
Divide both sides by 2.
y=5x
Now substitute this into the second equation.
Answer:
Step-by-step explanation:
y is 15.49
Formula is b = √c^2-a^2
You could use sine [ opposite/hypotenuse ],
Cosine [adjacent/hypotenuse]
or Tangent [ opposite/adjacent ]
to find theta
Theta is 75.522
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.