Answer:


Step-by-step explanation:


Multiply the numerator by the reciprocal of the denominator.





Multiply the numerator by the reciprocal of the denominator.


<h3>Hope it is helpful...</h3>
Answer:
400cm^2
Step-by-step explanation:
For this question, you need to find the surface areas of both objects, then add them together.
For the cube:
56cm for the front
56cm for the back
42cm for the side
42cm for the other side
48cm for the top
48cm for the bottom
SA for the cube: 292cm^2
For the triangle, things are a little different. We do the same process that we did to find the SA of the cube, but we do not have to find the SA of the top side (because there isn't a top side) and we have to divide the total SA by 2 because it's a triangle.
For the triangle:
42cm for the front
42cm for the back
54cm for the slanted side
42cm for the other side
36cm for the bottom
SA for the triangle: (216/2)^2=108cm^2
292+108=400cm^2
the SA of the composite figure is 400cm^2
Answer:
14 yd²
Step-by-step explanation:
4 • 7 = 28
Since this is a triangle you divide the answer by 2
28/2 = 14
14 yd²
Hope this helps dude
Answer:
CA = 5
Step-by-step explanation:
Since the sides are 3 and 4, we recognize this as a 3:4:5 right triangle, with CA = 5. Using the Pythagorean theorem confirms this:
CA² = AB² +BC²
CA² = 3² +4² = 9 +16 = 25
CA = √25
CA = 5
9514 1404 393
Answer:
(b) 15.32
Step-by-step explanation:
You can use your triangle sense to answer this.
The side x will always be shorter than the hypotenuse, 20. This eliminates the last two choices.
If the angle is 45°, then the sides are equal at about 0.707 times the length of the hypotenuse. That would make them 0.707×20 = 14.14. Since the angle is greater than 45°, the opposite side will be greater than 14.14. Only one answer choice fits between 14 and 20: the second choice -- 15.32.
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The mnemonic SOH CAH TOA reminds you of the relation ...
Sin = Opposite/Hypotenuse
sin(50°) = x/20
x = 20×sin(50°) . . . . multiply by 20 to find x
x ≈ 15.32 . . . . . . . . . use your calculator to evaluate
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The attachment is intended to show how the triangle side lengths change with angle.