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1 year ago

Find the area of the figure.

Mathematics

1 answer:

blondinia [14]1 year ago

5 0

I hope this helpssss :))

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Please help me i need help please

Oksanka [162]

90-70= 20
angle 4= 20
90-50= 40
angle 6= 40
90-15= 75
angle 8= 75

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3 years ago

If a bag contains 12 quarters, 6 dimes, and 18 nickles, what is the part-to-whole ratio of nickles to all coins?

zepelin [54]

Answer:

18/36 or 1/2

Step-by-step explanation:

There are 18 nickels, which is the numerator.

You add all the numbers together to get the denominator, which is 12+6+18=36.

Then, you put the two values in a fraction - 18/36

and simplify, to get you 1/2.

3 0

3 years ago

Somebody please help .. What is the exact volume of this right cone ?

stiks02 [169]

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=12\\
h=8
\end{cases}\implies V=\cfrac{\pi (12)^2(8)}{3}$

7 0

2 years ago

Write each ratio 3 different ways

Alenkasestr [34]

Answer:

I don't know the number of the ratio but i will create an example of 3 ways to write ratio

Let's use the number 10:8

you can write it like

10:8 (colon)
10 to 8
10/8 ( a fraction)

7 0

2 years ago

A right pyramid with a regular hexagon base has a height of 3 units If a side of the hexagon is 6 units long, then the apothem i

Setler79 [48]

Answer:

Part a) The slant height is $3\sqrt{2}\ units$

Part b) The lateral area is equal to $54\sqrt{2}\ units^{2}$

Step-by-step explanation:

we know that

The lateral area of a right pyramid with a regular hexagon base is equal to the area of its six triangular faces

$LA=6[\frac{1}{2}(b)(l)]$

where

b is the length side of the hexagon

l is the slant height of the pyramid

Part a) Find the slant height l

Applying the Pythagoras Theorem

$l^{2}=h^{2} +a^{2}$

where

h is the height of the pyramid

a is the apothem

we have

$h=3\ units$

$a=3\ units$

substitute

$l^{2}=3^{2} +3^{2}$

$l^{2}=18$

$l=3\sqrt{2}\ units$

Part b) Find the lateral area

$LA=6[\frac{1}{2}(b)(l)]$

we have

$b=6\ units$

$l=3\sqrt{2}\ units$

substitute the values

$LA=6[\frac{1}{2}(6)(3\sqrt{2})]=54\sqrt{2}\ units^{2}$

3 0

3 years ago

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