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3 years ago

5 hundreds 5 tens ×10

Mathematics

1 answer:

labwork [276]3 years ago

3 0

It would be 550x10 (5 tens = 50)

so you would solve for 550
 x10
5500

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What is 1% of 62 like i dont understand this

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1% of 62 would be 0.62

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Andre’s apartment is 800 square feet. If he wants to carpet 40% of it, how much carpet will he need?

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if the first and third of three consecutive odd integers are added, the result is 75 less than five times the second integers. f

Anastaziya [24]

Answer:

The third integer is 27

Step-by-step explanation:

Given

Represent the consecutive odd numbers with $T_1, T_2; and\ T_3$

Since they are consecutive odds, then

$T_2 = 2 + T_1$

$T_3 = 2 + T_2$

From the first statement in the question, we have that

$T_1 + T_3 = 5 T_2 - 75$

Required

Find the third integer

Recall that

Substitute $T_2 = 2 + T_1$ in $T_3 = 2 + T_2$

$T_3 = 2 + 2 + T_1$

$T_3 = 4 + T_1$

Substitute $T_3 = 4 + T_1$ and $T_2 = 2 + T_1$ in $T_1 + T_3 = 5 T_2 - 75$

$T_1 + 4 + T_1 = 5(2 + T_1) - 75$

Open Brackets

$T_1 + 4 + T_1 = 10 + 5T_1 - 75$

Collect like terms

$T_1 + T_1 + 4 = 5T_1 - 75 + 10$

$2T_1 + 4 = 5T_1 - 65$

Collect like terms

$2T_1 - 5T_1 = - 65 - 4$

$-3T_1 = - 69$

Divide both sides by -3

$\frac{-3T_1}{-3} = \frac{- 69}{-3}$

$T_1 = 23$

Recall that $T_3 = 4 + T_1$

$T_3 = 4 + 23$

$T_3 = 27$

The third integer is 27

6 0

3 years ago

Surface area of a equilateral by hand

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surface area of a equilateral by hand a 140.4 cm and 9cm

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3 years ago

You have 480 grams of a radioactive kind of samarium. If its half-life is 90 years,

lisov135 [29]

Answer:

120 grams will be left after 180 years.

Step-by-step explanation:

A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

$N(t)=N_0(\frac{1}{2})^\frac{t}{t_{1/2}}$

where,

$N(t)$ = quantity of the substance remaining

$N_0$ = initial quantity of the substance

$t$ = time elapsed

$t_{1/2}$ = half life of the substance

From the information given we know that:

The initial quantity is 480 g,
The half-life is 90 years,
180 years is the time elapsed.

And we want to find how much will be left. For this we use the above formula.

$N(t)=480\left(\frac{1}{2}\right)^{\frac{180}{90}}\\\\N(t)=480\left(\frac{1}{2}\right)^2\\\\N(t)=480\cdot \frac{1}{2^2}=120$

120 grams will be left after 180 years.

3 0

3 years ago