Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Answer:
38.2 %
Step-by-step explanation:
120/100 = 1.2 (average time)
(1.2 - 1.5)/1 = -.3
z table value for "-.3" is .3821
Associative property is when you move the grouping symbols: ( and )
So the answer is B.
Your question is so blur i cant see
plzz send a nice pics
