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3 years ago

What is the least number of plums that can be shared equally among 6, 9 or 12 children?

Mathematics

1 answer:

Luba_88 [7]3 years ago

5 0

Answer:

in order to find the least number of plums that can be shared, we have to find the greatest common factor of 6 ,9 and 12. the greatest common factor of 6 , 9 and 12 is 3. so if we have three plums. for 6 children , we have 3 plums.

Step-by-step explanation:

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Solve equation show all steps what 2x-3x+5=18

PSYCHO15rus [73]

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Let's solve your equation step-by-step.

$2x-3x+5=18$

Step 1: Simplify both sides of the equation.

$2x-3x+5=18\\2x + -3x + 5 = 18$

$( 2x + -3x ) + ( 5) = 18$ (Combine Like Terms)

$-x + 5 = 18\\-x + 5 = 18$

Step 2: Subtract 5 from both sides.

$-x + 5 - 5 = 18 - 5 \\-x = 13$

Step 3: Divide both sides by -1.

$\frac{-x}{-1} = \frac{13}{-1} \\x = -13$

Answer : $\boxed {x = -13}$

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Have a great day/night!

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3 0

3 years ago

Read 2 more answers

Which of these systems of equations would be best solved using the subtraction method?

Lynna [10]

Answer:

Step-by-step explanation:

1. x+2y=6 or x=6-2y

3x-2y=2

3(6-2y)-2y=2

18-6y-2y=2

18-8y=2

-8y=-18+2

-8y=-16

y=-16/-8

y=2 ans.

x+2*2=6

x+4=6

x=6-4=2 ans.

Proof:

3*2-2*2=2

6-4=2

2=2

I leave the rest for you to practice with.

3. 4x+y=7

2x+5y=-1

5. 3x+2y=-2

6x-y=6

Solve the system using the elimination method. Show all your steps.

7. -3x+3y=3

3x+y=9 add.

---------------------------------

4y=12

y=12/4

y=3 ans.

3x+3=9

3x=9-3

3x=6

x=6/3

x=2 ans.

Proof:

-3*2+3*3=3

-6+9=3

3=3

I'll leave the rest for practice.

9. -5x+12y=20

x-2y=-6

11. 3x+2y=1

4x+ 6y= 7

4 0

2 years ago

HALP HALP hALP HALP HALP

fiasKO [112]

Answer:

the answer is option (B)

4 0

3 years ago

Pls help!!

Allisa [31]

Answer:

Perimeter = 17a

Area = 30 square meters

Step-by-step explanation:

Perimeter = 2b + 8 = 10b + 5 + a = 15ab + 2a - b = 17a

Area = 2 + 8 = 10 + 2 = 12 × 5 = 60 simplify

I honestly don't know if this is correct, I hope it is

8 0

2 years ago

Read 2 more answers

Find all solutions of the given system of equations (If the system is infinite many solution, express your answer in terms of x)

lisov135 [29]

Answer:

(a) The system of the equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ has no solution.

(b) The system of the equations $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ has many solutions $y=\frac{2x}{3}-\frac{5}{3}$

Step-by-step explanation:

(a) To find the solutions of the following system of equations $\left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right.$ you must:

Multiply $2x-3y=3$ by 2:

$\begin{bmatrix}4x-6y=6\\ 4x-6y=3\end{bmatrix}$

Subtract the equations

$4x-6y=3\\-\\4x-6y=6\\------\\0=-3$

0 = -3 is false, therefore the system of the equations has no solution.

(b) To find the solutions of the system $\left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right.$ you must:

Isolate x for $4x-6y=10$

$x=\frac{5+3y}{2}$

Substitute $x=\frac{5+3y}{2}$ into the second equation

$16\cdot \frac{5+3y}{2}-24y=40\\8\left(3y+5\right)-24y=40\\24y+40-24y=40\\40=40$

The system has many solutions.

Isolate y for $4x-6y=10$

$y=\frac{2x}{3}-\frac{5}{3}$

3 0

3 years ago