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zysi [14]
3 years ago
13

If n(X)=200,x)=300 and n(XUY)=400

Mathematics
2 answers:
olga_2 [115]3 years ago
6 0

Answer:

{ \boxed{ \bf{formular : { \tt{n(X{ \small{U}Y) = n(X) + n(Y) - n(X{ \small{n}Y)}}}}}}} \\ n(X{ \small{n}}Y) = (200 + 300) - 400 \\  = 500 - 400 \\ { \boxed{n(X{ \small{n}}Y) = 100}} \\  \\ { \underline{ \blue{ becker \: jnr}}}

-BARSIC- [3]3 years ago
4 0
Thamaniya so much I need this so + er
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PLEASE HELP, I A NOT SURE IF THIS IS THE RIGHT ANSWER
Y_Kistochka [10]

Answer:

yeb it is

Step-by-step explanation:

6 0
3 years ago
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There are no universally accepted definitions of the ages of Millennials and Generation Xers; the consensus is that the former a
nadya68 [22]

Answer:

<u>A. The probability that a Millennial is married is 0.089 or 8.9%.</u>

<u>B. The probability that a Baby Boomer is single, never married is 0.03 or 3%.</u>

<u>C. The probability that one person selected randomly (female or male) is married is 0.513 or 51.3% </u>

<u>D. The probability that someone who is living with a partner, but not married is a Generation X is 0.025 or 2.5%.</u>

Step-by-step explanation:

According to the information provided on the analysis table, we can answer the questions:

A. The probability that a Millennial is married is 0.089 or 8.9%.

B. The probability that a Baby Boomer is single, never married is 0.03 or 3%.

C. The probability that one person selected randomly (female or male) is married is 0.513 or 51.3% (Millennial 0.089 + Generation X 0.223 + Baby boomer 0.201)

D. The probability that someone who is living with a partner, but not married is a Generation X is 0.025 or 2.5%.

7 0
2 years ago
A _[blank 1]_ is a number whose only factors are 1 and itself. If a number has other factors besides 1 and itself, it is called
kykrilka [37]

Numbers whose only factors are 1 and itself is known as prime numbers , numbers whose factors besides 1 and itself are composite numbers, we can use the sieve of Eratosthenes to determine whether the number is prime or composite.

Given a paragraph in which there are blanks:

A _____ is a number whose only factors are 1 and itself. If a number has  factors besides 1 and itself, it is called a _____. You can use divisibility rules or _______ to help you determine whether a number is prime or composite.

We are required to fill the blank with appropriate options.

We have to fill "prime numbers" in the first blank.

We have to fill "composite numbers" in the second blank.

We have to fill "the sieve of Eratosthenes" in the third blank.

Hence numbers whose only factors are 1 and itself is known as prime numbers , numbers whose factors besides 1 and itself are composite numbers, we can use the sieve of Eratosthenes to determine whether the number is prime or composite.

Learn more about prime numbers at brainly.com/question/145452

#SPJ1

3 0
1 year ago
What is the volume of a rectangular prism with a length of 5 cm, width of 4cm, and height of
Zepler [3.9K]

Answer:

180cm^3

Step-by-step explanation:

All you have to do is multiply everything together to get the volume. l x w x h

5 0
2 years ago
Read 2 more answers
Rename 5/6 and 14/15 using the least common denominator.
baherus [9]

Answer:

\frac{25}{30}~and~\frac{28}{30}

  • Multiply 5 by 5 to get your first parameter.

5 * 5 = 25

  • Multiply 6 by 5 to get the denominator, or your second parameter.

5 * 6 = 30

  • For the second fraction, \frac{14}{15}, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

14 * 2 = 28

  • Now, multiply 15 by 2

15 * 2 = 30

  • The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

25~and~30 -- > \frac{25}{30}

28~and~30-- > \frac{28}{30}

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

________________________________________________________

<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0
2 years ago
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