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3 years ago

Please help with my statistics

Mathematics

1 answer:

marissa [1.9K]3 years ago

3 0

Pretty sure it might be either B or C... No entirely sure...

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Fill in the blanks and explain the pattern.<br><br> XA, XB, XC, __,__,__

Anit [1.1K]

Answer:

XD,XE,XF

Step-by-step explanation:

XA,XB,XC,XD,XE,XF

IT IS BECAUSE OF THE ALPHABETICAL ORDER AFTER X

8 0

3 years ago

2. AB and DE are parallel. Angle BAC = 30 , angle CDE = 50. What is the measure of angle ACD?

inysia [295]

The correct answer is C. 80

3 0

3 years ago

Read 2 more answers

Antonio rented a bike from Alberto's Bikes. It cost $11 plus $4 per hour. If Antonio paid

Nina [5.8K]

Answer:

5 hours

Step-by-step explanation:

31-11 = 20

20/4 = 5

6 0

3 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago

Need help on this! Please someone help!!!

Jet001 [13]

This can be easily solved, especially with a calculator.
With the calculator, you can find that $\sqrt{42}$ is about 6.4807.
Multiply that by 2, you get about 13 inches.

If you can't use a calculator, then you can just estimate. Since we know that $\sqrt{36}$ is 6 and $\sqrt{49}$ is 7, $\sqrt{42}$ is in between them, so you can just say somewhere around 6.5.

Multiply 2 * 6.5 and you get 13 inches.

7 0

2 years ago