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RideAnS [48]
3 years ago
10

What is the difference between 3G andg3

Mathematics
1 answer:
lbvjy [14]3 years ago
6 0
Dosent make sense need more
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A doghouse is to be built in the shape of a right trapezoid, as shown below. What is the area of the doghouse?
Harman [31]
I hope this helps you

7 0
3 years ago
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Find the prime factorizations foor the following numbers 36 and 84
Varvara68 [4.7K]
Answer:

36 = 2² * 3²
84 = 2² * 3 * 7


Explanation:

Pf of 36 = 2 * 2 * 3 * 3 which then becomes 2 (to the power of 2) times 3 (to the power of 2)

Pf of 84 = 2 * 2 * 3 * 7 which then becomes 2 (to the power of 2) * 3 * 7

If this helps it would be greatly appreciated if you thanked me.
6 0
4 years ago
Can someone help answer this
kolezko [41]

Answer:

v = 55

Step-by-step explanation:

Plug in the values provided into the equation

v = u + at

v = 23 + 8 * 4

Solve

v = 23 + 8 * 4

v = 23 + 32

<u>v = 55</u>

6 0
3 years ago
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An elevator containing five people can stop at any of seven floors. What is the probability that no two people exit at the same
elena-s [515]

Answer:

Approximately 0.15 (360 / 2401.) (Assume that the choices of the 5 passengers are independent. Also assume that the probability that a passenger chooses a particular floor is the same for all 7 floors.)

Step-by-step explanation:

If there is no requirement that no two passengers exit at the same floor, each of these 5 passenger could choose from any one of the 7 floors. There would be a total of 7 \times 7 \times 7 \times 7 \times 7 = 7^{5} unique ways for these 5\! passengers to exit the elevator.

Assume that no two passengers are allowed to exit at the same floor.

The first passenger could choose from any of the 7 floors.

However, the second passenger would not be able to choose the same floor as the first passenger. Thus, the second passenger would have to choose from only (7 - 1) = 6 floors.

Likewise, the third passenger would have to choose from only (7 - 2) = 5 floors.

Thus, under the requirement that no two passenger could exit at the same floor, there would be only (7 \times 6 \times 5 \times 4 \times 3) unique ways for these two passengers to exit the elevator.

By the assumption that the choices of the passengers are independent and uniform across the 7 floors. Each of these 7^{5} combinations would be equally likely.

Thus, the probability that the chosen combination satisfies the requirements (no two passengers exit at the same floor) would be:

\begin{aligned}\frac{(7 \times 6 \times 5 \times 4 \times 3)}{7^{5}} \approx 0.15\end{aligned}.

5 0
2 years ago
What percent is 24 or 96
KIM [24]

Answer:

.25 or 25%

Step-by-step explanation:

24/96=.25

6 0
3 years ago
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