What is the difference between 3G andg3

(6x - 12)/3 + 4 = 18/x

svet-max [94.6K]

X=3
X=-3
Hope this help!

3 0

2 years ago

What is the domain of the function y= the square root of x+6-7

Diano4ka-milaya [45]

X>-6 is what i believe the answer is.
hope this helps!

4 0

3 years ago

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Please help me out with this so I can keep my kitten.

notka56 [123]

Answer:

$y = \frac{32}{3}$

Step-by-step explanation:

Firstly, move over the negative 3/4 fraction (don't forget to swap the operation i.e subtract to add):

$\frac{y}{8} = \frac{7}{12} + \frac{3}{4}$

Now, to add the two fractions, simply multiply the numerator and denominator by 3:

$\frac{3*3}{4*3} = \frac{9}{12}$

Now add this to the other fraction:

$\frac{9}{12} + \frac{7}{12} = \frac{16}{12}$

This can be simplified down by dividing both the numerator and denominator by 4:

$\frac{4}{3}$

Which now simplifies the original equation to:

$\frac{y}{8} = \frac{4}{3}$

Remove the y out of the fraction:

$\frac{1}{8}y = \frac{4}{3}$

Now multiply both sides by 8:

$(\frac{1}{8}y) * 8 = (\frac{4}{3}) * 8$

$y = \frac{4*8}{3}$

$y = \frac{32}{3}$

Hope this helps!

5 0

2 years ago

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Rename 600,000= ten thousands

lyudmila [28]

For this case we have the following number:

600,000

We can rewrite this number as the product of two numbers.

We have then, mathematically:

600,000 = 60 * 10,000

Then, rewriting in words we have:

600,000 = sixty - ten thousand s

Answer:

Rewriting 600,000 we have:

600,000 = sixty - ten thousands

4 0

2 years ago

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Assume that in a particular military exercise involving two units, Red and Blue, thereis a 60 % chance that the Red unit will su

Marysya12 [62]

Answer: a) There are 42% chances that both units will meet their objectives.

b) There are 88% chances that one or the other but not both of the units will be successful.

Step-by-step explanation:

Since we have given that

Probability that the Red unit will successfully meet its objectives = 60% = P(R)

Probability that Blue unit will successfully meet its objectives = 70% = P(B)

Probability that only Red unit will be successful = P(only Red) = 18%

As we know that

$P(only\ red)=P(R)-P(R\cap B)\\\\0.18=0.60-P(R\cap B)\\\\0.18-0.60=-P(R\cap B)\\\\-0.42=-P(R\cap B)\\\\P(R\cap B)=42\%$

Hence, there are 42% chances that both units will meet their objectives.

the probability that one or the other but not both of the units will be successful is given by

$P(R\cup B)=P(R)+P(B)-P(R\cap B)\\\\P(R\cup B)=0.60+0.70-0.42\\\\P(R\cup B)=0.88\\\\P(R\cup B)=88\%$

Hence, there are 88% chances that one or the other but not both of the units will be successful.

6 0

2 years ago