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Ket [755]
3 years ago
13

Gordan and Harry had 340 marble,altogether.After Gordan gave away 2/5 of his marbles and harry gave away 20 of his marbles, they

had the same number of marbles left. How many marbles did Harry have in the end? Remember to draw the model
Mathematics
1 answer:
BARSIC [14]3 years ago
6 0
109.8
you take 240 and subtract that from 2/5.Then you subtract 20 and that gives you 219.6.Since they have the same amount of marbles left,you have to divide 219.6 by 2 and your answer is 109.8
(I just used a calculator)
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2 years ago
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The table shows a proportional relationship between the number of stars Roberto collects in a game and his total points. A row o
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Answer:

1) 20 stars; 30 points.

2) 28 stars, 42 points.

3) 38 stars, 57 points.

Step-by-step explanation:

<h3> The missing table is attached.</h3>

Let  be "x" the numbers of stars Roberto collects and "y" his total points.

The proportional relationship has this form:

y=kx

Where "k" is the constant of proportionality.

We can choose the point (8,12) from the table, where:

x=8\\y=12

Substituting these values into  y=kx and solving for "k", we get:

 12=k(8)\\\\\frac{12}{8}=k\\\\k=1.5

Knowing the value of "k", we determine that the  following Numbers of stars and the Total points could be used as the missing values in the table:

1) For x=20 :

y=(1.5)(20)=30

2) For x=28 :

y=(1.5)(28)=42

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4 0
3 years ago
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Does anyone know how to solve this? It’s really starting to stress me out.
bekas [8.4K]

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lim(x→2) (sin(πx) + 8 − x³) / (x − 2)

If we substitute x = u + 2:

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lim(u→0) (sin(πu + 2π) + 8 − (u + 2)³) / u

Distribute the cube:

lim(u→0) (sin(πu + 2π) + 8 − (u³ + 6u² + 12u + 8)) / u

lim(u→0) (sin(πu + 2π) + 8 − u³ − 6u² − 12u − 8) / u

lim(u→0) (sin(πu + 2π) − u³ − 6u² − 12u) / u

Using angle sum formula:

lim(u→0) (sin(πu) cos(2π) + sin(2π) cos(πu) − u³ − 6u² − 12u) / u

lim(u→0) (sin(πu) − u³ − 6u² − 12u) / u

Divide:

lim(u→0) [ (sin(πu) / u) − u² − 6u − 12 ]

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lim(u→0) (sin(πu) / u) − 12

Multiply and divide by π.

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π lim(u→0) (sin(πu) / (πu)) − 12

Use special identity, lim(x→0) ((sin x) / x ) = 1.

π (1) − 12

π − 12

3 0
2 years ago
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