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Ket [755]
3 years ago
13

Gordan and Harry had 340 marble,altogether.After Gordan gave away 2/5 of his marbles and harry gave away 20 of his marbles, they

had the same number of marbles left. How many marbles did Harry have in the end? Remember to draw the model
Mathematics
1 answer:
BARSIC [14]3 years ago
6 0
109.8
you take 240 and subtract that from 2/5.Then you subtract 20 and that gives you 219.6.Since they have the same amount of marbles left,you have to divide 219.6 by 2 and your answer is 109.8
(I just used a calculator)
You might be interested in
Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista
poizon [28]
The rate of Car A is x
The rate of Car B is x - 5

They travel the same distance. So we can make an equation:

4(x) = 4.5(x-5)

Solve for x.

4(x) = 4.5(x-5)
4x = 4.5x - 22.5

Subtract 4.5x on both sides

-0.5x = -22.5

Divide by -0.5 on both sides
x = 45

But we want the speed of Car B which is x - 5

So Car B's speed is 45 - 5 = 40

Your answer is 40
8 0
3 years ago
Please help me! Screenshot of question is attached. 15 Points and Brainliest to the correct answer.
ehidna [41]

Hello,

I would love to answer but there is no screenshot to see!


7 0
3 years ago
What’s the answer???
azamat

Answer:

C = 6.28 in.

A = 3.14 in.^2

Step-by-step explanation:

C = (pi)d

C = 3.14 * 2 in.

C = 6.28 in.

A = (pi)r^2

r = d/2 = 2 in./2 = 1 in.

A = 3.14 * (1 in.^2)

A = 3.14 in.^2

7 0
3 years ago
Read 2 more answers
Can someone help please
Jlenok [28]

1/2

plsss mark brainliestt

Step-by-step explanation:

3/6

1.5/3

5/2.5

5 0
3 years ago
If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by​
PIT_PIT [208]

Answer:

The family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|} (1)

Where:

\theta - Angle between vectors, in sexagesimal degrees.

\|\vec a\|, \|\vec b \| - Norms of vectors \vec {a} and \vec{b}

If \theta is acute, then the cosine function is bounded between 0 a 1 and if we know that \vec {a} = (p, 3, -7) and \vec {b} = (p, -p, 4), then the possible values for p are:

Minimum (\cos \theta = 0)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0

Maximum (\cos \theta = 1)

\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1

With the help of a graphing tool we get the family of possible values for p are:

(-\infty, -4) \,\cup \,(7, +\infty)

7 0
3 years ago
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