There are 1952.31g of nickel can be converted to the carbonyl with 3.55 m³ of CO at 100.7 kPa.
Given data
The reaction can be written as:
Ni+4CO ⟶
V(CO)=3.55
T=50°C=323.5K
p=100700Pa
Now, use the formula:
pV=nR*T
Where, P is pressure, V is volume and T is temperature. n=p∗V / R∗T
n=100700∗3.55 / 8.314∗323.15
It is known that,
n(CO)=133.059mol
n(Ni)=n(CO)/4=33.26mol
Mass can be determined by the formula:
Mole = mass / molar mass
Now, put the value of given data in above formula:
m(Ni)=nAr=33.26mol/58.69g/mol
m(Ni)=1952.31g
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Long answer- 6.79166666667
Short answer- 6.791
I think that is the short answer, if not I apologize. Have a wonderful day! :)
Answer:you observe the light?
Explanation:
Answer:
-470.4 kJ/mol
Explanation:
Balanced reactions equations are as follows.
CaC2 (s) + 2H2O (l) â C2H2 (g) + CaOH2 (s) ÎH=â414.kJ
6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ
To get the 6 C2H2 we need to multiply first equation by 6
Then we get
6CaC2 (s) + 12H2O (l) â 6C2H2 (g) + 6CaOH2 (s) ÎH=â414.kJ * 6 = -2484 kJ
6C2H2 (g) + 3CO2 (g) + 4H2O (g) â 5CH2CHCO2H (g) ÎH=132.kJ
So the total energy produced = -2484 kJ + 132.0 kJ = -2352 kJ
This amount of energy is given out for the 5 moles of acid
So lets convert it for 1 mol
-2352 kJ * 1 mol / 5 mol = -470.4 kJ/mol
So the delta H of reaction for the formation of the acrylic acid is -470.4 kJ/mol
Answer:
Empirical formula is KHO₃C.
Explanation:
Given data:
Percentage of potassium = 39.0%
Percentage of hydrogen = 1.01%
Percentage of carbon = 12.0%
Percentage of oxygen = 47.9%
Empirical formula = ?
Solution:
Number of gram atoms of K = 39.0/ 39 = 1
Number of gram atoms of H = 1.01 / 1.01 = 1
Number of gram atoms of O = 47.9 / 16 = 3
Number of gram atoms of C = 12 / 12 = 1
Atomic ratio:
K : H : O : C
1/1 : 1/1 : 3/1 ; 1/1
1 : 1 : 3 : 1
K : H : O :C = 1: 1 : 3 : 1
Empirical formula is KHO₃C.
