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grandymaker [24]
3 years ago
11

A compound contains 39.0% potassium, 1.01% hydrogen, 12.0% carbon and 47.9% oxygen. Find its empirical formula

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

Empirical formula is  KHO₃C.

Explanation:

Given data:

Percentage of potassium = 39.0%

Percentage of hydrogen = 1.01%

Percentage of carbon = 12.0%

Percentage of oxygen = 47.9%

Empirical formula = ?

Solution:

Number of gram atoms of K = 39.0/ 39 = 1

Number of gram atoms of H = 1.01 / 1.01 = 1

Number of gram atoms of O = 47.9 / 16 = 3

Number of gram atoms of C = 12 / 12 = 1

Atomic ratio:

K               :            H                  :      O            :      C

1/1              :             1/1                :     3/1          ;       1/1

 1              :              1                  :        3          :        1

K : H : O :C =  1: 1 : 3 : 1

Empirical formula is  KHO₃C.

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A rigid cylinder with a movable piston contains a sample of hydrogen gas. At 330. K, this sample has a pressure of 150. kPa and
Marta_Voda [28]

Answer:

V₂ = 4.34 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 3.50 L

Initial pressure = 150 Kpa (150/101.325 = 1.5 atm)

Initial temperature = 330 K

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ =  1.5 atm ×  3.50 L × 273 K / 330 K × 1 atm

V₂ = 1433.3 atm .L. K / 330 k.atm

V₂ = 4.34 L

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3 years ago
Which of the following is a balanced chemical equation? A, H2O2 → H2O + O2
LenKa [72]
I believe it's D! Hope you can help with my question!
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3 years ago
If an acid has a ka=1.6x10^-10, what is the acidity of the solution?
LUCKY_DIMON [66]
The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
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Name two compounds with more exothermic lattice energies than scandium oxide and justify your choice.
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Answer:

1 . Al_2O_3

2. TiO_2

Explanation:

The more stable the ionic compound, the more is it lattice energy.

  • The more the charge on the cation and the anion, the greater is the lattice energy.
  • The less the size of the cation and the anion, the greater is the lattice energy.

Scandium oxide (Sc_2O_3) is an oxide in which Sc^{3+} behaves as cation and O^{2-} behaves as anion.

The compounds which has higher lattice energy than scandium oxide are:

1 . Al_2O_3

This is because the charge are same on the cation and the anion as in the case of the Scandium oxide but the size of the cation Al^{3+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

2. TiO_2

This is because the charge on the cation Ti^{4+} is greater than that of Sc^{3+} and also the size of the cation Ti^{4+} is smaller than Sc^{3+}. Thus, this corresponds to higher lattice energy.

3 0
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Answer:

by mixing red and yellow

Explanation:

7 0
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