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grandymaker [24]
3 years ago
11

A compound contains 39.0% potassium, 1.01% hydrogen, 12.0% carbon and 47.9% oxygen. Find its empirical formula

Chemistry
1 answer:
Ipatiy [6.2K]3 years ago
4 0

Answer:

Empirical formula is  KHO₃C.

Explanation:

Given data:

Percentage of potassium = 39.0%

Percentage of hydrogen = 1.01%

Percentage of carbon = 12.0%

Percentage of oxygen = 47.9%

Empirical formula = ?

Solution:

Number of gram atoms of K = 39.0/ 39 = 1

Number of gram atoms of H = 1.01 / 1.01 = 1

Number of gram atoms of O = 47.9 / 16 = 3

Number of gram atoms of C = 12 / 12 = 1

Atomic ratio:

K               :            H                  :      O            :      C

1/1              :             1/1                :     3/1          ;       1/1

 1              :              1                  :        3          :        1

K : H : O :C =  1: 1 : 3 : 1

Empirical formula is  KHO₃C.

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How many unpaired electrons are present in a ground-state atom from each of the following groups?
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For 7A(17) :

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<h3>What are Unpaired Electrons?</h3>
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6 0
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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Natasha2012 [34]

When carbon reacts with oxygen it forms CO2. This can depicted by the below equation.

C + O2→ CO2

It has been mentioned that when 14.4 g of C reacts with 53.9 g of O2, then 15.5 g of O2 remains unreacted. <u>This indicates that Carbon is the limiting reagent and hence the amount of CO2 produced is based on the amount of Carbon burnt.</u>

C + O2→ CO2

In the above equation , 1 mole of carbon reacts with 1 mole of O2 to produce 1 mole of CO2.

In this case 14.4 g of Carbon reacts with 53.9 of O2 to produce "x"g of CO2.

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No of moles of O2 = (Total mass of O2 burned - Mass of unreacted O2)/32

No of moles of O2 = (53.9-15.5) ÷ 32 = 1.2 moles.

Hence as already discussed 1 mole of Carbon reacts with 1 mole of O2 to produce 1 mole of CO2. In this case 1.2 moles of carbon reacts with 1.2 moles of O2 to produce 1.2 moles of CO2.

Moles of carbon dioxide = Mass of CO2 produced /Molar mass of CO2

Mass of CO2 produced(x) = Moles of CO2 ×Molar mass of CO2

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