What is the first law of radiation?

2 answers:

6 0

Answer:The first law of thermal radiation states that each square meter of a hotter object’s surface emits more light at all wavelengths. What this means is that if you compare two objects that are giving off heat, and one object is hotter than the other, each square meter of the surface of that object emits more light than the cooler object at every wavelength of light.

Explanation:

suter [353]3 years ago

3 0

Kirchhoff's law of thermal radiation.In heat transfer, Kirchhoff's law of thermal radiation refers to wavelength-specific radiative emission and absorption by a material body in thermodynamic equilibrium, including radiative exchange equilibrium. A body at temperature T radiates electromagnetic energy.

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In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive

aev [14]

Answer:

In the next generation of 4000 children, 1680 of them will be heterozygous for the eye colour.

Explanation:

There's a population of 2500, 2275 of with have brown eyes and 225 blue eyes. Let's call the dominant allele associated with brown colour "B" and the recessive allele associated with blue colour "b". So the possible genotypes are BB, Bb and bb, being BB and Bb brown eyed individuals and bb blue eyed individuals.

If the population it's in Hardy-Weinberg equilibrium, it means genotypic and allelic frequencies don't change from one generation to the following.

From the information given, we can calculate both allelic and genotypic frequencies.

First, we know that the frequency of the genotype bb it's the amount of blue eyed individuals over the total population.

f(bb)=225/2500=0.09

Additionally we know the allelic frequencies can be related to the genotypic ones when the population it's in Hardy-Weinberg equilibrium. Particularly we can say:

f(bb)=[f(b)]^2 => f(b)=[f(bb)]^(1/2)= 0.3 (square root of f(bb)).

Also, we can calculate the frequency of the B allele, as the probability of all alleles of the gene sum 1. In other words:

f(b)+f(B)=1 => f(B)=1 - f(b) = 1 - 0.3 = 0.7

So far, we have calculated the allelic frequencies, f(b)=0.3 and f(B)=0.7.

Now we can calculate the genotypic frequencies, using the equations of the Hardy-Weinberg equilibrium.

f(bb)=[f(b)]^2 => f(bb)=0.3^2=0.09
f(Bb)=2*f(B)*f(b) => f(Bb)=2*0.7*03=0.42
f(BB)=[f(B)]^2 => f(BB)=0.7^2=0.49

Finally, knowing that there are 4000 children in the next generation, to know how many of them are expected to be heterozygous for the eye colour, we should multiply the number of children for the probability of being heterozygous for the eye colour (which is the genotypic frequency for the genotype Bb).