What is the greatest common factor of 96 48 84

Porphyrin is a pigment in blood protoplasm and other body fluids that is significant in body energy and storage. Let x be a rand

SOVA2 [1]

Answer:

Question 1:

(a) P(x<60) = 0.9236

(b) P(x>16) = 0.9564

(c) P(16<x<60) = 0.88

(d) P (x>60) = 0.0764

Question 2:

(a) P(x<3) = 0.0668

(b) P(x>7) = 0.0062

(c) P(3<x<7) = 0.927

Step-by-step explanation:

Question 1:

x = no. of mg of porphyrin per deciliter of blood.

μ = 40

σ = 14

(a) We need to compute P(x<60). We need to find the z-score using the normal distribution formula:

z = (x - μ)/σ

P(x<60) = P((x - μ)/σ < (60 - 40)/14)

= P(z < 20/14)

= P(z<1.43)

Using the normal distribution probability table we can find the value of p at z=1.43.

P(z<1.43) = 0.9236

so, P(x<60) = 0.9236

(b) P(x>16) = P(z>(16-40)/14)

= P(z>-1.71)

= 1 - P(z<-1.71)

= 1 - 0.0436

P(x>16) = 0.9564

(c) P(16<x<60) = P((16-40)/14) < x < (60-40)/14)

= P(-1.71 < z < 1.43)

This probability can be calculated as: P(z<1.43) - P(z<-1.71)

P(16<x<60) = 0.9236 - 0.0436

P(16<x<60) = 0.88

(d) P(x>60) = 1 - P(x<60)

we have calculated P(x<60) in part (a) so,

P(x>60) = 1 - 0.9236

P (x>60) = 0.0764

Question 2:

μ = 4.5 mm

σ = 1.0 mm

In this question, we will again compute the z-scores and then find the probability from the normal distribution table.

(a) P(x<3) = P(z<(3-4.5)/1)

= P(z<-1.5)

P(x<3) = 0.0668

(b) P(x>7) = 1 - P(x<7)

= 1 - P(z<(7-4.5)/1)

= 1 - P(z<2.5)

= 1 - 0.9938

P(x>7) = 0.0062

(c) P(3<x<7) = P(x<7) - P(x<3)

we have computed both of these probabilities in parts (a) and (b) so,

P(3<x<7) = 0.9938 - 0.0668

P(3<x<7) = 0.927

6 0

2 years ago

A girl is snorkeling 1 meter below sea level and then dives down another 4.5 meters. How far below sea level is the girl?

san4es73 [151]

Answer:

5.5 Meters below sea level

Step-by-step explanation:

Since sea level is at 0 meters, the girl is already 1 meter below sea level. When she dives down another 4.5 meters, you just add

1 + 4.5 = 5.5

and that's your answer

:)

4 0

3 years ago

PLEASE HELP ASAP......!!!!!!

Musya8 [376]

Answer:

If you roll two dices, you can get as results all numbers from 2 to 12. Among these, the prime numbers are 2, 3, 5, 7, 11. The probability you get each of them is: 2: you can get it only as 1+1, so one combination over 36 possibility. Probability: 1/36. 3: you can get it as 1+2 or 2+1, so two combinations over 36 possibility. Probability: 2/36. 5: you can get it as 1+4, 2+3, 3+2, 4+1, so four combinations over 36 possibility. Probability: 4/36. 7: you can get as 1+6, 2+5, 3+4, 4+3, 5+2, 6+1, so six combinations over 36 possibility. Probability: 6/36. 11: you can get it as 5+6 or 6+5 so two combinations over 36 possibility. Probability: 2/36. The total probability of getting a prime number is the sum of the probabilities, which is 15/36. So m=15, n=36 and 10m+n=150+36=186.

7 0

2 years ago

What is the value of the digit 8 in alaska's population

Montano1993 [528]

Ten thousands is the answer

4 0

3 years ago

If the weight (in grams) of cereal in a box of Lucky Charms is N(489,6), what is the probability that the box will contain less

Wittaler [7]

Answer:

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

N(489,6)

This means that $\mu = 489, \sigma = 6$

What is the probability that the box will contain less than the advertised weight of 466 g?

This is the p-value of Z when X = 466. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{466 - 489}{6}$

$Z = -3.83$

$Z = -3.83$ has a p-value of 0.000064

0.000064 = 0.0064% probability that the box will contain less than the advertised weight of 466 g.

3 0

2 years ago