Forces: What’s Going to Happen?

2. Which of the following is an example of acceleration.

N76 [4]

C
<span>Write at least 20 characters to explain it well.</span>

3 0

3 years ago

Read 2 more answers

Choose all that represent ways that Venus is different than Earth.

Ganezh [65]

The answer is C because carbon dioxide is trapped in a thick atmosphere.

7 0

4 years ago

A book light has a 1.4 W, 4.8 V bulb that is powered by a transformer connected to a 120 V electric outlet. The secondary coil o

VLD [36.1K]

Answer:

Turns of the primary coil: 500

Current in the primary coil: Ip= 0.01168A

Explanation:

Considering an ideal transformer I can propose the following equations:

Vp×Ip=Vs×Is

Vp= primary voltaje

Ip= primary current

Vs= secondary voltaje

Is= secondary current

Np×Vs=Ns×Vp

Np= turns of primary coil

Ns= turns of secondary coil

From these equations I can clear the number of turns of the primary coil:

Np= (Ns×Vp)/Vp = (20×120V)/4.8V = 500 turns

To determine the current in the secondary coil I use the following equation:

Is= (1.4W)/4.8V = 0.292A

Therefore I can determine the current in the primary coil with the following equation:

Ip= (Vs×Is)/Vp = (4.8V×0.292A)/120V = 0.01168A

5 0

3 years ago

Why do spring balances show reading After long use

sweet [91]

Answer:

When spring balances have been used for a long time, elastic fatigue is developed. So, the spring balances will no longer show the right readings.

Explanation:

Hope this helps u

Crown me as brainliest:)

5 0

3 years ago

An object of mass 30KG is falling in air and experiences a force due to air resistance of 50 newtons determine the net force act

ryzh [129]

Answer:

Assume that $g = 10\; \rm N \cdot kg^{-1}$ . The net force on this object will be $250\; \rm N$ (downwards.) The acceleration of this object will be approximately $8.3\; \rm m \cdot s^{-2}$ (also downwards.)

Explanation:

<h3>Net force</h3>

The object is falling towards the ground because of gravity. The size of the gravitational force on this object depends on its mass and the strength of the gravitational field at its location.

Near the surface of the earth, the gravitational field strength is approximately $10\; \rm N \cdot kg^{-1}$ . In other words, approximately $10\; \rm N$ of gravitational force acts on each kilogram of mass near the surface of the earth.

The mass of this object is given as $m = 30\; \rm kg$ . Therefore, the size of the gravitational force on it will be:

$W = m \cdot g \approx 30 \; \rm kg \cdot 10\; N \cdot kg^{-1} = 300\; \rm N$ .

Near the surface of the earth, gravitational forces point towards the ground. On the other hand, the direction of air resistance on this object will be opposite to its direction of motion. Since this objects is moving towards the ground, the air resistance on it will be directed in the opposite direction. That's exactly the opposite of the direction of the gravitational force on this object. The net force on this object will be:

$300\; \rm N - 50\; \rm N =250\; \rm N$ .

<h3>Acceleration</h3>

Let $a$ denote the acceleration on this object. Apply Newton's Second Law of motion:

$\begin{aligned} a &= \frac{F(\text{net force})}{m} \approx \frac{250\; \rm N}{30\; \rm kg} \approx 8.3\; \rm m \cdot s^{-2}\end{aligned}$ .

Note that the acceleration of this object and the net force on it should be in the same direction.

8 0

3 years ago